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Nana76 [90]
3 years ago
8

Find the equation that can represent the situation if the sum of two numbers is 32. We also know that the greater number is 5 mo

re than the smaller number. (5 points)
a
x + (x + 5) = 32

b
x − (x + 5) = 32

c
x(x + 5) = 32

d
x(x − 5) = 32
Mathematics
1 answer:
Serhud [2]3 years ago
4 0

Answer:

A. x+(x+5)=32

Step-by-step explanation:

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The chances are 1/6 because 6-8 is 1/6 of the possible timings.

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add 3+3

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4 years ago
Jose equation is -4(x+2) = 8x+16 says to jill “I can solve for the variable in this equation in at least 4 different ways
erastovalidia [21]

Answer:

that is step 1 and step 2 and step3

step 4

Let's solve your equation step-by-step.

−4(x+2)=8x+16

Step 1: Simplify both sides of the equation.

−4(x+2)=8x+16

(−4)(x)+(−4)(2)=8x+16(Distribute)

−4x+−8=8x+16

−4x−8=8x+16

Step 2: Subtract 8x from both sides.

−4x−8−8x=8x+16−8x

−12x−8=16

Step 3: Add 8 to both sides.

−12x−8+8=16+8

−12x=24

Step 4: Divide both sides by -12.

−12x

−12

=

24

−12

x=−2

Answer:

x=−2

6 0
4 years ago
I WILL AWARD BRAINLIEST!! PLEASE HELP!!
Veseljchak [2.6K]

Answer:

1)\\\large\boxed{x=\dfrac{a+c}{b},\ if\ b\neq0}\\\\2)\\\boxed{if\ a=\dfrac{63b}{23}\ then\ x\ is\ any\ real \ number}\\\\\boxed{if\ a\neq\dfrac{63b}{23}\ then\ x\ not\ exist\ (no\ solution)}

Step-by-step explanation:

1)\\a-(a+b)x=(b-a)x-(c+bx)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\a-ax-bx=bx-ax-c-bx\qquad\text{cancel}\ bx\ \text{on the right side}\\\\a-ax-bx=-ax-c\qquad\text{add}\ ax\ \text{to both sides}\\\\a-bx=-c\qquad\text{subtract}\ a\ \text{from both sides}\\\\-bx=-a-c\qquad\text{divide both sides by}\ -b\neq0\\\\x=\dfrac{-a-c}{-b}\\\\x=\dfrac{a+c}{b}

2)\\2(3x-5a)+9(2a-7b)+3(5a-2x)=0\\\\\text{use the distributive property}\ a(b+c)=ab+ac\\\\(2)(3x)+(2)(-5a)+(9)(2a)+(9)(-7b)+(3)(5a)+(3)(-2x)=0\\\\6x-10a+18a-63b+15a-6x=0\qquad\text{combine like terms}\\\\(6x-6x)+(-10a+18a+15a)-63b=0\\\\23a-63b=0\qquad\text{add}\ 63b\ \text{to both sides}\\\\23a=63b\qquad\text{divide both sides by 23}\\\\a=\dfrac{63b}{23}\\\\if\ a=\dfrac{63b}{23}\ then\ x\ is\ any\ real \ number\\\\if\ a\neq\dfrac{63b}{23}\ then\ x\ not\ exist\ (no\ solution)

3 0
4 years ago
Is -13 an interger, whole number, real number, rational number, irrational number, or natural number
Irina-Kira [14]
-13 is a real number and a rational number.
It's not an interger, because there's no such thing.
But it IS an integer.
5 0
3 years ago
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