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3 years ago

Which of the following equations could be used to find the value of 3,550 ÷ 25?

Mathematics

1 answer:

fiasKO [112]3 years ago

8 0

Answer:

<em>A is correct answer</em>

Step-by-step explanation:

$(3000 + 500 + 50) \div 25 \\$

$(3550) \div 25$

$= = > 3550 \div 25$

Thanks

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Brilliant_brown [7]

Answer:

Step-by-step explanation:

Corresponding angles of both the squares are congruent. (angles of a square measure 90°)

Ratio of the sides of the given squares = $\frac{\text{Side length of small square}}{\text{Side length of the large square}}$

= $\frac{2}{5}$

This ratio of side lengths is constant for all corresponding sides.

Therefore, corresponding sides are proportional.

Since, all angles of both the squares are congruent and all the sides are proportional, both the squares will be similar.

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= $\frac{5}{2}$

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3 years ago

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3 years ago

Given: Triangles ABC and DBC are isosceles, m∠BDC = 30°, and m∠ABD = 155°. Find m∠ABC, m∠BAC, and m∠DBC.

just olya [345]

∠BDC=30, so ∠CBD + ∠BCD=180-30=150
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ΔABC is isosceles, so ∠ABC=∠ACB=80
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3 years ago

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NeTakaya

Answer:

I am sorry but I do not know

Step-by-step explanation:

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3 years ago

Read 2 more answers

If we are given x such that 25^x-9^y=18 and 5^x-3^y=3, compute 5^x+3^y.

leonid [27]

25 = 5*5 and 9 = 3*3, which we can exploit to write

$25^x-9^y=(5^2)^x-(3^2)^y=5^{2x}-3^{2y}=(5^x)^2-(3^y)^2$

so that this expression is actually a difference of squares. We can factorize this to get

$(5^x-3^y)(5^x+3^y)=18$

and given that $5^x-3^y=3$ , we divide both sides by this to get

$5^x+3^y=\dfrac{18}3=\boxed{6}$

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3 years ago