Answer:
m∠FEH = 44°
m∠EHG = 64°
Step-by-step explanation:
1) The given information are;
The angle of arc m∠FEH = 272°, the measured angle of ∠EFG = 116°
Given that m∠FEH = 272°, therefore, arc ∠HGF = 360 - 272 = 88°
Therefore, angle subtended by arc ∠HGF at the center = 88°
The angle subtended by arc ∠HGF at the circumference = m∠FEH
∴ m∠FEH = 88°/2 = 44° (Angle subtended at the center = 2×angle subtended at the circumference)
m∠FEH = 44°
2) Similarly, m∠HGF is subtended by arc m FEH, therefore, m∠HGF = (arc m FEH)/2 = 272°/2 = 136°
The sum of angles in a quadrilateral = 360°
Therefore;
m∠FEH + m∠HGF + m∠EFG + m∠EHG = 360° (The sum of angles in a quadrilateral EFGH)
m∠EHG = 360° - (m∠FEH + m∠HGF + m∠EFG) = 360 - (44 + 136 + 116) = 64°
m∠EHG = 64°.
Answer:
Solve for
x
by simplifying both sides of the inequality, then isolating the variable.
Step-by-step explanation:
I think it’s B) 30 degrees
Answer:
576 ways
Step-by-step explanation:
There are 4 choices for the column of pawn in the 1st row
There are 3 choices for the column of pawn in the 2nd row,
There are 2 choices for the column of pawn in the 3rd row, and
There is 1 choice for the column of the pawn in the 4th row
Which gives a total of 4! = 24
Also, the pawns are distinct, so there are 4! ways to place them in these chosen positions;
4! = 24
So, there are 24 * 24 possible ways
= 576 ways
