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JulijaS [17]
3 years ago
15

What is 4 1/3 divided by 10 1/5

Mathematics
1 answer:
vladimir2022 [97]3 years ago
6 0
I got 65/153 since you actually multiply by the reciprocal of the second fraction.
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pleaseeee help!!! What is the 21st term in the arithmetic sequence in which a3 is 59 and a7 is 103 (enter only the term)
GuDViN [60]

Answer: 257

Step-by-step explanation:

Given that:

a3 = 59

a7 = 103

The nth term of an Arithmetic Progression (A. P) is given by:

an = a1 + (n-1)d

Where a1 = first term of the sequence ;

d = common difference

Therefore a3 = 59 can be represented thus:

a3 = a1 + (3-1)d = 59

a3 = a1 + 2d = 59 - - - - (1)

a7 = 103

a7 = a1 + (7-1)d = 103

a7 = a1 + 6d = 103 - - - - - (2)

Subtracting (2) from (1)

(2d - 6d) = (59 - 103)

-4d = - 44

d = 11

Substitute d= 11 into (1)

a1 + 2d =59

a1 + 2(11) = 59

a1 + 22 = 59

a1 = 59 - 22

a1 = 37

The 21st term:

a21 = a1 + (21 - 1)d

a21 = 37 + 20(11)

37 + 220 = 257

6 0
3 years ago
What is the value of f(–1)?
Kryger [21]
Personally,you may need to declassify the form of details of function f,

6 0
3 years ago
Read 2 more answers
3(0.5x-4)=3/2x-1.2 plz answerrr
natita [175]

Answer:

NO solution, this statement is not true.

Step-by-step explanation:

Distribute

1.5x-12=3/2x-1.2

Combine Like terms

1.5x=3/2x+10.8

Combine like terms

0=10.8

NO solution! 0 is NOT equal to 10.8!

6 0
3 years ago
What values of b satisfy 3(2b + 3)^2 = 36?
goldfiish [28.3K]
3(2b + 3)² = 36

Divide both sides by 3.

3(2b + 3)² / 3 = 36/3

(2b + 3)² = 12

Take the square root of both sides.

√(2b + 3)² = √12

(2b +3) = +√12 or -√12

Solving when:

2b + 3 =  +√12                                                        2b + 3 =  -√12

2b = √12 - 3                                                            2b = -√12 - 3

b = (√12 - 3)/2        √12 ≈ 3.46                              b = (-√12 - 3)/2

 b ≈  (3.46 - 3)/2                                                       b ≈  (-3.46 - 3)/2

b ≈ 0.46/2                                                                   b ≈ -6.46/2

b ≈ 0.23                                                                        b ≈ -3.23

Therefore  b ≈ 0.23  or  -3.23       

Hope this helps.
5 0
3 years ago
Find the tenth term of the expansion (x+ y)¹³
Anon25 [30]

Answer:

715x^4y^9

Step-by-step explanation:

Given

(x + y)^{13

Required

Determine the 10th term

Using binomial expansion, we have:

(a + b)^n = ^nC_0a^nb^0 + ^nC_1a^{n-1}b^1 + ^nC_2a^{n-2}b^2 +.....+^nC_na^{0}b^n

For, the 10th term. n = 9

So, we have:

(a + b)^n = ^nC_{9}a^{n-9}b^{9

(x + y)^{13} = ^{13}C_{9}x^{13-9}y^9

(x + y)^{13} = ^{13}C_{9}x^4y^9

Apply combination formula

(x + y)^{13} = \frac{13!}{(13-9)!9!}x^4y^9

(x + y)^{13} = \frac{13!}{4!9!}x^4y^9

(x + y)^{13} = \frac{13*12*11*10*9!}{4!9!}x^4y^9

(x + y)^{13} = \frac{13*12*11*10}{4!}x^4y^9

(x + y)^{13} = \frac{13*12*11*10}{4*3*2*1}x^4y^9

(x + y)^{13} = \frac{17160}{24}x^4y^9

(x + y)^{13} = 715x^4y^9

Hence, the 10th term is 715x^4y^9

3 0
3 years ago
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