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Dimas [21]
3 years ago
13

Find the range of the following data set. 11,5, 1, 11, 12 01 1. 017

Mathematics
1 answer:
polet [3.4K]3 years ago
5 0

Answer:

range 11

Step-by-step explanation:

The range is the largest number minus the smallest number

The largest number is 12 and the smallest number is 1

12 - 1 = 11

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The Russo-Japanese War was a conflict between Russia and Japan that started in the year 190419041904. Let xxx represent any year
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The first thing we must do for this case is to define a variable.
 We have then:
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 We write now the inequality that models the problem.
 We know that the conflict began in the year 1904, therefore, all the previous years are given by:
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 Answer:
 
an inequality in terms of x and 1904 that is true only for values of x that represent years before the start of the Russo-Japanese War is:
 
x <1904
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Which of the following is not equivalent
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To find if a fractions are equivalent, divide the numerator by the denominator for each fraction.

45/70=0.642857
27/42=0.642857
9/14=0.642857
63/98=0.642857

Notice how all of these get you the same number. However, when you divide 90 by 137, you get 0.64748, which is not the same as the others. Therefore, 90/137 is the fraction that is not equivalent to 45/70.

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What is the answer to this too?
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The Students' Conjectures Emily and Zach have two different polynomials to multiply: Polynomial product A: (4x2 – 4x)(x2 – 4) Po
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Complete Question:

Emily and Zach have two different polynomials to multiply: Polynomial product A: (4x2 – 4x)(x2 – 4) Polynomial product B: (x2 + x – 2)(4x2 – 8x) They are trying to determine if the products of the two polynomials are the same. But they disagree about how to solve this problem.

Answer:

A = B

Step-by-step explanation:

<em>See comment for complete question</em>

Given

A: (4x^2 - 4x)(x^2 - 4)

B: (x^2 + x - 2)(4x^2 - 8x)

Required

Determine how they can show if the products are the same or not

To do this, we simply factorize each polynomial

For, Polynomial A: We have:

A: (4x^2 - 4x)(x^2 - 4)

Factor out 4x

A: 4x(x - 1)(x^2 - 4)

Apply difference of two squares on x^2 - 4

A: 4x(x - 1)(x - 2)(x+2)

For, Polynomial B: We have:

B: (x^2 + x - 2)(4x^2 - 8x)

Expand x^2 + x - 2

B:(x^2 + 2x - x - 2)(4x^2- 8x)

Factorize:

B:(x(x + 2) -1(x + 2))(4x^2- 8x)

Factor out x + 2

B:(x -1) (x + 2)(4x^2- 8x)

Factor out 4x

B:(x -1) (x + 2)4x(x- 2)

Rearrange

B: 4x(x - 1)(x - 2)(x+2)

The simplified expressions are:

A: 4x(x - 1)(x - 2)(x+2) and  

B: 4x(x - 1)(x - 2)(x+2)

Hence, both polynomials are equal

A = B

3 0
3 years ago
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