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uranmaximum [27]
4 years ago
9

the histogram below represents the high temperatures recorded each day over a one month period. 7 days=80-82 degrees Celsius, 9

days=82-84 degrees Celsius, 6 days=84-86 degrees Celsius, 5 days=86-88 degrees Celsius, and 3 days=88-90 degrees Celsius. How many days had a temperature of below 86?
Mathematics
2 answers:
pantera1 [17]4 years ago
4 0
Assuming that the histogram is represented by the given numbers:

7 days = 80 to 82 degrees Celsius
9 days = 82 to 84 degrees Celsius
6 days = 84 to 86 degrees Celsius
5 days = 86 to 88 degrees Celsius
3 days = 88 to 90 degrees Celsius

The days with a temperature below 86 degrees Celsius are day 7, 9, and 6.  <span />
lana [24]4 years ago
4 0

Answer:

The number of days temperature is below 86 is:

  22 days

Step-by-step explanation:

We are given the following data:

7 days=80-82 degrees Celsius.

9 days=82-84 degrees Celsius.

6 days=84-86 degrees Celsius.

5 days=86-88 degrees Celsius.  

3 days=88-90 degrees Celsius.

The number of days temperature is below 86 is:

22 days   (7+9+6)

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Y = 4x – 18<br> y = -5x +9
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Answer:

(3, -6)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = 4x - 18

y = -5x + 9

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em> [2nd Equation]:                                                                           4x - 18 = -5x + 9
  2. [Addition Property of Equality] Add 5x on both sides:                                   9x - 18 = 9
  3. [Addition Property of Equality] Add 18 on both sides:                                   9x = 27
  4. [Division Property of Equality] Divide 9 on both sides:                                  x = 3

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Substitute in <em>x</em> [1st Equation]:                                                                           y = 4(3) - 18
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