Step-by-step explanation:
HCF of 60 and 84 = 6
So the required greatest number that divides 60 and 84 without leaving remainder is 6.
I would say the answer is 2
9514 1404 393
Answer:
Step-by-step explanation:
In the left problem, you use the fact that <em>the sum of the segment lengths is equal to the overall length</em>.
AC +CB = AB
(3x -4) +(x -2) = 62
4x -6 = 62 . . . . . collect terms
4x = 68 . . . . . . . add 6
x = 17 . . . . . . . . . . divide by 4
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In the right problem, you use the fact that <em>the sum of the angles is equal to the overall angle</em>. Here, that overall angle is a linear angle, so measures 180°.
∠DFG +∠GFE = ∠DFE
(5y +3) +(2y -5) = 180
7y = 182 . . . . . . . . . . . . . . collect terms, add 2
y = 26 . . . . . . . . . . . . . . . .divide by 7
Answer:
1st: 3*root6 + 5
2nd: 35*root2 + 115
3rd: 24*root2 - 20*root6 + 15*root3 - 18
4th: 17*root6 - 38
5th: 13*root10 - 42
Step-by-step explanation:
To simplify these expressions we need to use the distributive property:
(a + b) * (c + d) = ac + ad + bc + bd
So simplifying each expression, we have:
1st.
(2 root 2 + root 3 ) ( 2 root 3 - root 2)
= 4*root6 - 2*2 + 2*3 - root6
= 3*root6 - 4 + 9
= 3*root6 + 5
2nd.
(root 5 + 2 root 10) (3 root 5 + root 10)
= 3 * 5 + root50 + 6*root50 + 2*10
= 15 + 5*root2 + 30*root2 + 100
= 35*root2 + 115
3rd.
(4 root 6 - 3 root 3) (2 root 3 - 5)
= 8*root18 - 20*root6 - 6*3 + 15root3
= 24*root2 - 20*root6 + 15*root3 - 18
4rd.
(6 root 3 - 5 root 2 ) (2 root 2 - root 3)
= 12*root6 - 6*3 - 10*2 + 5*root6
= 17*root6 - 18 - 20
= 17*root6 - 38
5th.
(root 10 - 3 ) ( 4 - 3 root 10)
= 4*root10 - 3*10 - 12 + 9*root10
= 13*root10 - 30 - 12
= 13*root10 - 42
