<u>Answer- </u>
In tossing four fair dice, the probability of getting at most one 3 is 0.86.
<u>Solution-</u>
The probability of getting at most one 3 is, either getting zero 3 or only one 3.
( ∵ xxxx )
( ∵ 3xxx, x3xx, xx3x, xxx3 )
P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86
The answer to this question is y=3
Answer:
1. 5IN = 9 OUT
2. -3 IN= -7 OUT
3. 4 IN = 7 OUT
4. -9 IN = -20 OUT
Step-by-step explanation:
Here I have attached a photo to help you with this:
Answer:
Step-by-step explanation:
the figure is divided into a cube and a cuboid
for the cube,
volume = a^3
= 6^3 = 216 cm^3
for the cuboid,
volume = l × b × h
= 13 × 6 × 6
=468 cm^3
so total volume = volume of the cube + volume of the cuboid
= 216 + 468
=684 cm^3
hope this helps
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