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3 years ago

4

Which expression can be used to approximate the expression below, for all positive numbers a, b, and x, where a Not-equals 1 and

b Not-equals 1? log Subscript x Baseline x

2 answers:

Orlov [11]3 years ago

7 0

Answer:

The answer would b a.) logb(x)/logb(a)

Hope this helps!

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nevsk [136]3 years ago

3 0

Answer:

A.

Step-by-step explanation:

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Each lap around the park is 0.58 mile. Jessica walked 3.25 laps around the park. How many miles did Jessica walk around the park

Fynjy0 [20]

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Step-by-step explanation:

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3 years ago

A man is in a boat 2 miles from the nearest point on the coast. He is to go to point Q, located 3 miles down the coast and 1 mil

mafiozo [28]

Answer:

The answer is "0.45385".

Step-by-step explanation:

The time is taken to reach the coast $= \frac{\sqrt{(2^2 + x^2)}}{4}$

The time is taken to reach Q after reaching the coast $= \frac{\sqrt{(1 + (3-x)^2)}}{4}$

Total time, $T= \frac{\sqrt{(1 + (3-x)^2)}}{4}+ \frac{\sqrt{(1 + (3-x)^2)}}{4}$

This has to be minimum,

$\to \frac{dt}{dx} = 0$

$\to \frac{\sqrt{(2^2 + x^2)}}{2} + \frac{\sqrt{1 + (3-x)^2}}{3}\\\\ \frac{x}{4}\sqrt{(4+x^2)} + \frac{(x-3)}{(4\sqrt{(x^2-6x+10)}} = 0\\\\\frac{x^2}{16} \times (4+x^2) = \frac{(x-3)^2}{16 \times (x^2-6x+10)}\\\\x^2(4+x^2) = \frac{(x-3)^2}{(x^2-6x+10)}\\\\4x^2+x^4 = \frac{ x^2+9-6x}{(x^2-6x+10)}\\\\ 4x^2+x^4(x^2-6x+10) = x^2+9-6x\\\\4x^4-24x^3+40x^2+x^6-6x^5+10x^4= x^2+9-6x\\\\x^6-6x^5+ 14x^4-24x^3+39x^2+6x-9=0\\\\$

x=0.45385

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3 years ago