Hey can you please help me posted picture of question :)
2 answers:
Answer:
The roots are -3+√6 and -3-√6
Explanation:
First, we would need to put the equation in standard form which is as follows:
ax² + bx + c = 0
This can be done as follows:
x² + 6x + 9 - 6 = 0
x² + 6x + 3 = 0
By comparison:
a = 1
b = 6
c = 3
Now, to get the roots, we will need to used the quadratic formula shown in the attached image.
By substitution, we would find that:
either x = -3 + √6
or x = -3 - √6
Hope this helps :)
The roots are -3+√6 and -3-√6
Explanation:
First, we would need to put the equation in standard form which is as follows:
ax² + bx + c = 0
This can be done as follows:
x² + 6x + 9 - 6 = 0
x² + 6x + 3 = 0
By comparison:
a = 1
b = 6
c = 3
Now, to get the roots, we will need to used the quadratic formula shown in the attached image.
By substitution, we would find that:
either x = -3 + √6
or x = -3 - √6
Hope this helps :)
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Answer:
The positive value of will result in exactly one real root is approximately 0.028.
Step-by-step explanation:
Let , roots are those values of
so that
. That is:
(1)
Roots are determined analytically by the Quadratic Formula:
The smaller root is , and the larger root is
.
has one real root when
. Then, we solve the discriminant for
:
The positive value of will result in exactly one real root is approximately 0.028.