Let the numbers be x and y
x= y-2.... (1)
and, 2y = 16 + 4x.... (2)
putting the value of x from (1) in (2),
2y = 16 + 4x
=> 2y = 16 + 4(y-2)
=> 2y = 16 + 4y - 8
=> 2y = 8 + 4y
=> 2y - 4y = 8
=> -2y = 8
=> y =-8/2
=> y= -4
and x = -4-2 = -6
hence , in short the numbers are -2 and -4
Answer:
hope this helps
Step-by-step explanation:
3*2 * 1 = 24 ways . It is called arrangement or permutations, while if you need to group some objects it is called combination and there we need to consider unique groups only.
The zeros of the function occur when the graph meet the x-axis so in this case the zeros occur at B ( 0 and 5)
Answer:
-1
Step-by-step explanation:
using PEDMAS(parentheses, exponents, division, multiply, addition, subtraction) to solve the problem
First, multiply (-5)(2) and 2(-3)
(-5)(2) – 2(-3) + 3
=-10-(-6)+3
=-10+6+3
add -10+6
-4+3
Add -4+3
-4+3
=-1
Therefore, (-5)(2) – 2(-3) + 3 is equal to -1
Answer:
10 and 12 are two even integers whose product =120
Step-by-step explanation:
10 and 12 are two even integers whose product =120
