Answer:
Dalton didn't ride any kilometer farther since he keeps threading in the same path as that of his father.
Step-by-step explanation:
If Dalton's dad rode 1 kilometer north, 2 kilometers west 1 kilometer south and 2 kilometers east, then he has been moving in a rectangular path.
If Dalton rode in the same path 5times, then Dalton's has not move farther than his dad since he is still moving in the same rectangular path. He is only expending more energy.
Their final destination will still be the same for both of them no matter how many times Dalton keeps threading in the same path.
We use FOIL method to multiply this out. First termsOuter termsInner termsLast terms Product = (3m3 * 3m3) + (3m3 * -1/2y) + (-1/2y * 3m3) + (-1/2y * -1/2y) Product = 9m6 - (3/2)m3y - (3/2)m3y + (1/4)y2 <span>Product = 9m6 - 3m3y + (1/4)y<span>2</span></span>
Y = mx + c, where m is your gradient and c is your y intercept.
If the line is perpendicular to the line y = 3x - 5, the line's gradient = -(1/3) as when it comes to perpendicular bisector, m1/m2 = -1
y = -(1/3)x + C
To find C sub in x=2 and y=2 as it goes through (2,2)
2 = -(1/3)2 + C
2 = -(2/3) + C
2 + 2/3 = C
C = 8/3
There your equation of a line is
y = -(1/3)x + 8/3
<span>let:
X = the distance of the bottom of the ladder from the wall at any time
dX/dt = rate of travel of the bottom of the ladder = 1.1 ft/sec
A = the angle of the ladder with the ground at anytime
dA/dt = rate of change of the angle in radians per second
X = 10 cos A
dX/dt= -10 sin A dA/dt = 1.1
dA/dt = -1.1/(10 sinA)
When X = 6; cosA = 6/10; sinA = 8/10
Therefore:
dA/dt = -1.1/(10 x 0.8) = -0.1375 radiant per second. </span>
Answer:
work is shown and pictured
