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irinina [24]
3 years ago
9

Please help me with this surds question.

Mathematics
1 answer:
noname [10]3 years ago
3 0

the answer is 0.2 or one fifths

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RIP OpenStudy ;(
klemol [59]
First note that \frac{2^n+1}{2^{n+1}} =  \frac{2^n}{2^{n+1}} + \frac{1}{2^{n+1}} = \frac{1}{2} + \frac{1}{2^{n+1}}

If you take limit, then you have \lim_{n \to \infty}( \frac{1}{2} + \frac{1}{2^{n+1}})= \lim_{n \to \infty}( \frac{1}{2}) +\lim_{n \to \infty}(\frac{1}{2^{n+1}})=\frac{1}{2} +0= \frac{1}{2}



3 0
3 years ago
Read 2 more answers
HURRY PLEASEEEEEEEEEEEEEEEEEEEEEEEE
dexar [7]

Answer:i would say 1

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A drug company is testing a new drag which is supported to reduce blood pressure. From the nine people who are used as subjects,
Pie

Answer:

The 95% confidence interval for the mean change in blood pressure, \bar{x}, is 1.744 < \bar{x} < 2.816

Step-by-step explanation:

The parameters given are;

The number of people in the sample, n = 9

The average drop in blood pressure, \bar{x} = 2.28 points

The standard deviation, σ = 0.82

The confidence level = 95%

The formula for confidence interval with a known mean is given as follows;

CI=\bar{x}\pm z_{\alpha/2} \dfrac{\sigma}{\sqrt{n}}

Where:

z_{\alpha/2} = z - score at 95% confidence level = 1.96

We therefore have;

CI=2.28 \pm 1.96 \times \dfrac{0.82}{\sqrt{9}}

Which gives the 95% confidence interval for the mean change in pressure, \bar{x}, is given as follows;

1.744 < \bar{x} < 2.816

6 0
3 years ago
Write an expression that represents the product of a variable and a negative number
lbvjy [14]
-6x because this expression represents the product of a negative number (-6) and a variable (x).
4 0
3 years ago
Jennifer is flying a kite. She is looking up at the kite at an angle of elevation of 39º. If the hand that is holding the kite s
inn [45]

See attachment for answer.

5 0
2 years ago
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