Answer:
13.89% of students are willing to report cheating by other students.
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 180
Number of students who reported cheating, x = 25
We have to find the proportion of the students are willing to report cheating by other students.
Proportion of students can be calculate as
Thus, 13.89% of students are willing to report cheating by other students.
Answer:
-2\3
Step-by-step explanation:
Answer:
20,18,16,14,12,10,8,6,4,2
10,9,8,7,6,5,4,3,2,1
Step-by-step explanation:
Pattern A:
Rule : start with 20 and subtract 2
Pattern B:
Rule : Start with 10 and subtract 1
Pattern 1:
20 - 2 = 18
18 - 2 = 16
16 - 2 = 14
14 - 2 = 12
12 - 2 = 10
10 - 2 = 8
8 - 2 = 6
6 - 2 = 4
4 - 2 = 2
20,18,16,14,12,10,8,6,4,2
Pattern 2:
10 - 1 = 9
9 - 1 = 8
8 - 1 = 7
7 - 1 = 6
6 - 1 = 5
5 - 1 = 4
4 - 1 = 3
3 - 1 = 2
2 - 1 = 1
10,9,8,7,6,5,4,3,2,1
Answer:
B. binomial with n = 5 and p = 1/6
Step-by-step explanation:
Given that James reads that 1 out of 6 eggs contains salmonella bacteria.
So he never uses more than 5 eggs in cooking.
If eggs do or don't contain salmonella independently of each other, then
probability for any one egg to contain salmonella bacteria is the constant 1/6.
Also there are only two outcomes, either bacteria present or not.
Hence the number of contaminated eggs when James uses 5 chosen at random has the distribution is Binomial
Here n = no of trials = no of eggs he uses = 5
Probability = 1/6
So option B is right.
Answer: The answer will be 8x.
Step-by-step explanation:
