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mylen [45]
3 years ago
11

Evaluate the expression 517-4)2 + 3 + 11. Need ASAP

Mathematics
1 answer:
goblinko [34]3 years ago
6 0

Answer:

1040

Step-by-step explanation:

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2 years ago
Evaluate 2/3x for x = 3/4. Please show your work.<br> Thank you!!! :)
GenaCL600 [577]
X = 3/4
So substitute x for 3/4 in <span> 2/3x
(3/4) x (2/3)

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5 0
3 years ago
1 point) Are the functions f,g, and h given below linearly independent? f(x)=e3x+cos(5x), g(x)=e3x−cos(5x), h(x)=cos(5x). If the
Fynjy0 [20]

Answer:

Functions are linearly dependent (are not linearly independent.)

Step-by-step explanation:

Remember that two functions f(x), g(x) and h(x) are said linearly independent on an interval I if the <em>only solution</em> to the equation

\alpha f(x)+\beta g(x)+\omega h(x)=0, \ \text{for all } x\in I

is the trivial one: α = 0, β = 0, ω = 0. If they are not linearly independent, they are called linearly dependent.

Now, let f(x), g(x) and h(x) be the functions:

f(x)=e^{3x}+\cos(5x),

g(x)=e^{3x}-\cos(5x),

h(x)=\cos(5x).

Then, letting α = 1, β= -1 and ω = -2, we see that:

\alpha f(x)+\beta g(x)+ \omega h(x)=e^{3x}+\cos(5x)-e^{3x}+\cos(5x)+2\cos(5x)=0.

Hence, the functions f(x), g(x) and h(x) are not linearly independent, or equivalently, are linearly dependent.

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3 years ago
How do I write the exponent expression below in numbers
Irina-Kira [14]

Answer:

(3^6)/2

Step-by-step explanation:

make sure everything as the numerator is in parenthesis

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