Answer:
5000
Step-by-step explanation:
Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
Answer:
Length: 40 Width: 76
Step-by-step explanation:
W is width, and L is length.
We know that the length is 36 less than the width, so L = w - 36. Two times the width plus two times the length equals the perimeter, so set up the equation for the perimeter as:
232 = 2w + 2(w-36)
Now solve for w:
232 = 2w + 2w - 72
304 = 4w
w = 76
we now know that the width is 76, so solve for the length:
L= 76-36
L = 40
The answer is to the question is 9
Answer: -2.5
Step-by-step explanation:
The average can be found by adding up the numbers then dividing by how many numbers there are in this case there are two numbers.
-30+25=-5
-5/2 = -2.5
