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musickatia [10]

2 years ago

5

Can you help I'm confused

2 answers:

Lady bird [3.3K]2 years ago

5 0

Answer:

x <= 5

Step-by-step explanation:

mark me brainliest

Brrunno [24]2 years ago

4 0

Answer:

x ≤ 5

Step-by-step explanation:

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Help please help please

solmaris [256]

Answer:

57

Step-by-step explanation:

due to the 2 parallel lines , we have the sum of them = 180

so we can solve the equation and get x.

(180 - 14 +5 )/ 3 = 57

5 0

2 years ago

35 points!!!! WILL GIVE BRAINLIEST

Arturiano [62]

Answer

Find out the length of OP .

To prove

As given

In △JKL, JO=44 in.

Now as shown in the diagram.

JP , MK, NL be the median of the △JKL and intresection of the JP , MK, NL be O .

Thus O be the centroid of the △JKL .

The centroid divides each median in a ratio of 2:1 .

Let us assume x be the scalar multiple of the OP and JO .

As given

JO = 44 in

2x = 44

x = 22 in

Thus the length of the OP IS 22 in .

7 0

3 years ago

Read 2 more answers

What is the decimal form of -4 7/8

svetlana [45]

$-4\frac{7}{8}=-4\frac{7\cdot125}{8\cdot125}=-4\frac{875}{1000}=\boxed{-4.875}$

4 0

2 years ago

One integer is 3 times another if the product of the two integers is 75 then find the integers

Kitty [74]

Answer: HOPE THIS HELPED! :D

5 x 15 = 75

Step-by-step explanation:

15 is 3x 5

and product do 3x15 is 75

so answer would be

5 & 15

6 0

2 years ago

The Municipal Transit Authority wants to know if, on weekdays, more passengers ride the northbound blue line train towards the c

Kitty [74]

Answer:

The 90% confidence interval $-49.8$

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 < \mu_2$

The distribution test statistics is $t = -3.222$

The rejection region is p-value < $\alpha$

The decision rule is reject the null hypothesis

The conclusion is

There is sufficient evidence to conclude that there are more passengers riding the 8:30 train

The p-value is $p-value =0.000951$

Step-by-step explanation:

From the question we are told that

The first sample size $n_1 = 30$

The first sample mean is $\= x _1 = 323$

The first standard deviation is $s_1 = 41$

The second sample size is $n_2 = 45$

The second sample mean is $\=x_2 = 356$

The second standard deviation is $s_2 = 45$

given that the confidence level is 90% then the level of significance is mathematically represented as

$\alpha = (100 -90)\%$

$\alpha = 0.10$

Generally the critical value of $\frac{\alpha }{2}$ obtained from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the pooled variance is mathematically represented as

$s^2 = \frac{(n_1 - 1)s_1^2 + (n_2 -1)s_2^2 }{n_1 + n_2 -2}$

$s^2 = \frac{(30 -1)(41^2) + (45-1)45^2}{30+45 -2}$

$s^2 = 1888.34$

Generally the standard error is mathematically represented as

$SE = \sqrt{\frac{s^2}{n_1} + \frac{s^2}{n_2} }$

=> $SE = \sqrt{\frac{1888.34}{30} + \frac{1888.34}{45} }$

=> $SE = 10.24$

Generally the margin of error is mathematically evaluated as

$E = Z_{\frac{\alpha }{2} } * SE$

$E = 1.645* 10.24$

$E = 16.85$

Generally the 90% confidence interval is mathematically represented as

$\=x_1 -\=x_2 -E < \mu_1 -\mu_2 < \=x_1 -\=x_2 +E$

$323 -356 -16.84$

$-49.8$

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 < \mu_2$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \=x_2 }{SE}$

=> $t = \frac{323-356}{10.24}$

=> $t = -3.222$

Generally the degree of freedom is mathematically represented as

$df = n_1+n_2 -2$

$df = 30 + 45 -2$

$df = 73$

The p-value is obtained from the student t distribution table at degree of freedom of 73 at 0.05 level of significance

The value is $p-value =0.000951$

Here the level of significance is $\alpha = 5\% = 0.05$

Given that the p-value < $\alpha$ then we reject the null hypothesis

Then the conclusion is

There is sufficient evidence to conclude that there are more passengers riding the 8:30 train

5 0

3 years ago