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3 years ago

Solve 8x=72. The solution is x=

Mathematics

2 answers:

prisoha [69]3 years ago

5 0

So you divide 8 in each side and you will get X=9

tino4ka555 [31]3 years ago

4 0

x = 9.

To get there, we can divide both sides by 8, to get from 8x to x.

8x / 8 = 72 / 8.

x = 9

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As a bench carpenter, you are building a shelf unit that will be placed in a 37 inch wide opening. You need to leave 6 inched on

Firlakuza [10]

The answer is B:31 inches, 37-6 is 31, therefore your answer

8 0

4 years ago

What is the range of this piecewise function

White raven [17]

Answer as a compound inequality: $-4 \le y < 2$

Answer in interval notation: [-4, 2)

=============================================

Explanation:

The range is the set of all possible y outputs of a function. When dealing with a graph like this, we just look at the highest and lowest points to determine which y values are possible.

The lowest point occurs when y = -4. We include this value. So far we have $y \ge -4$ which is the same as $-4 \le y$

The upper ceiling for the y value is y = 2. We can't actually reach this value because of the open hole at (-3,2). So we say that $y < 2$

Combine $-4 \le y$ and $y < 2$ to get the compound inequality $-4 \le y < 2$

This says y is between -4 and 2, including -4 but excluding 2.

To convert this to interval notation, we write [-4, 2) where the square bracket says to include the endpoint and the curved parenthesis says to exclude the endpoint.

6 0

3 years ago

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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5 0

3 years ago

Read 2 more answers

HAVE TO TURN IN TODAY PLZ HELP

erma4kov [3.2K]

The area equation is $A = \pi (4)^{2}$ , which when solved equals 50.24. That's the third answer on your list.

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3 years ago

Please help. Thank you

bezimeni [28]

Answer:

Step-by-step explanation:

look where the plot is Set 1 is at 8 and Set 2 is at 10. obviously 10 is greater than 8

8 0

3 years ago