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Misha Larkins [42]
3 years ago
5

Can u PLSSSSSSSSSSSSSSSSSSS answer this and show ur work

Mathematics
2 answers:
pshichka [43]3 years ago
8 0

Answer:

10 degrees

Step-by-step explanation:

The answer is 10 degrees because the angle is complementary which means its going to be 90 degrees so all you have to do to find the answer is add 50+30 and boom 10 degrees

Yuki888 [10]3 years ago
3 0
<h3>Answer:   80</h3>

====================================================

Explanation:

There are probably many approaches here, but one way to do this is to extend segment DO to form a line. Check out the diagram below. This line is in red.

The goal is to have this line extend to intersect with line AB. Let's call this intersection point E.

In that diagram, I've marked the variable y as angle EOB. Notice that angles BEO and CDO are congruent alternate interior angles (since lines AB and CD are parallel). So that's where that extra 30 degree angle comes from.

Focus on triangle EOB. The three angles of any triangle always add to 180

E+O+B = 180

30+y+50 = 180

y+80 = 180

y = 180-80

y = 100

The last step is to solve the equation below for x

x+y = 180

x+100 = 180

x = 180-100

x = 80

This works because angles x and y are supplementary. They form a straight angle.

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natali 33 [55]

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Step-by-step explanation:  

Given that;

If V₁ ....... V₄ are in R⁴ and V₃ = 2V₁ + V₂ then {V₁, V₂, V₃, V₄} is linearly dependent.  

Lets {V₁, V₂, V₃, V₄}  are linearly dependent

Then there exist a scalars C₁, C₂, C₃, C₄

So that C₁V₁ + C₂V₂ + C₃V₃ + C₄V₄ = 0

where at least one of the Ci ≠ 0.  

Take C₃ ≠  0 then we have V₃ = (C₁V₁ + C₂V₂ + C₄V₄) / C₃

V₃ is a linear combination of V₁, V₂ and V₄}

that is

Given V₃ = 2V₁ + V₂

⇒ 2V₁ + V₂ - V₃ = 0

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Here, C₁ = 1, C₂ = 1,  C₃ = -1 and C₄ = 0

So that {V₁, V₂, V₃, V₄} is linearly dependent.

therefore option B id the right answer.

- True. The vector V₃ is a linear combination of V₁ and V₂, so at least one of the vectors in the set is a linear combination of the others and set is linearly dependent.  

4 0
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