Can u PLSSSSSSSSSSSSSSSSSSS answer this and show ur work
2 answers:
<h3>Answer: 80</h3>
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Explanation:
There are probably many approaches here, but one way to do this is to extend segment DO to form a line. Check out the diagram below. This line is in red.
The goal is to have this line extend to intersect with line AB. Let's call this intersection point E.
In that diagram, I've marked the variable y as angle EOB. Notice that angles BEO and CDO are congruent alternate interior angles (since lines AB and CD are parallel). So that's where that extra 30 degree angle comes from.
Focus on triangle EOB. The three angles of any triangle always add to 180
E+O+B = 180
30+y+50 = 180
y+80 = 180
y = 180-80
y = 100
The last step is to solve the equation below for x
x+y = 180
x+100 = 180
x = 180-100
x = 80
This works because angles x and y are supplementary. They form a straight angle.
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Answer:
Kindly check explanation
Step-by-step explanation:
Given the data :
Rearranged data:
5, 5, 5, 5, 6, 7, 7, 7, 8, 12, 12, 13, 13, 15, 18, 18, 27, 28, 36, 48, 52, 60, 66, 94
Start time for Suriname = 694
Mean = ΣX / n
Mean = (567 + 694) / (24 + 1) = 1261 / 25 = 50.44
B.) median start Time for initial 24 values
0.5(n+1)th term
0.5(25) = 12.5th term
(13 + 13) / 2 = 13
C.) preferred measure of center for the distribution will be the median as it shapes well in the middle of the distribution. The mean is overestimated
d) Compute the quartiles (Q1, Q2, Q3), and find the IQR for these data. Are there outliers in the time to start a business data set? If so, identify and name any outliers.
Using calculator :
Lower quartile Q1 --> 7
Median Q2 --> 13
Upper quartile Q3 --> 42
IQR = (Q3 - Q1) = 42 - 7 = 35
OUTLIER:
Lower bound : Q1 - 1.5(IQR) ; 7 - 1.5(35) = - 45.5
Upper bound : Q3 + 1.5(IQR) = 42 + 1.5(35) = 94.5
Outlier : values below - 45.5 and above 94.5
Hence, Surimanes start time is the only Outlier.
e)
Standard deviation for 24 countries :
Standard deviation = sqrt[Σ(X - mean)^2 / (N - 1)]
Usibg calculator :
Standard deviation for the 24 countries is 23.83
f)
Standard deviation
