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3 years ago

What is one tenth of 24

1 answer:

6 0

So,

One tenth of 24 is the same as this:
$\frac{1}{10} * \frac{24}{1}$

Multiply
$\frac{24}{10}\ or\ \frac{12}{5}\ or\ 2 \frac{2}{5}\ or\ 2.4$

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What is the volume of the prism if they gave 15 feet and 12 feet

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144

Step-by-step explanation:

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4 years ago

Is is 24, 15, 23 or 33

vodka [1.7K]

Answer:

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3 years ago

Use the GCF to factor 28x + 42.<br> HELLP PLS

natima [27]

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3 years ago

The following graph shows a proportional relationship.

elena-s [515]

Answer:

The constant of proportionality is thus 1

Step-by-step explanation:

Note that the green line passes through (6, 6) and has a y-intercept of 0. Thus, the equation of the line is y = (6/6)x + 0, or y = x, or y = 1x.

The constant of proportionality is thus 1, which is also the slope of this line.

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3 years ago

fair coin is tossed three times. What is the probability that all three tosses land on heads,given that:(a) the first toss lands

maxonik [38]

Answer:

(a) The probability that all three tosses land on heads given that the 1st toss lands on Heads is $\frac{1}{4}$ .

(b) The probability that all three tosses land on heads given that at least one toss lands on heads is $\frac{1}{7}$ .

Step-by-step explanation:

The sample space of tossing 3 coins is:

S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} = 8 outcomes.

(a)

The sample space such that the 1st toss lands on Heads is:

S₁ = {HHH, HHT, HTH, HTT} = 4 outcomes.

The probability that all three tosses land on heads given that the 1st toss lands on Heads is:

P (3 Heads | 1st toss is Heads) = $\frac{P(3\ Heads\ \cap \ 1st\ toss\ is\ Heads)}{P(1st\ toss\ is\ Heads)}$

$=\frac{\frac{1}{4} }{\frac{4}{8} } \\=\frac{1}{8}\times \frac{8}{4}\\ =\frac{1}{4}$

Thus, the probability that all three tosses land on heads given that the 1st toss lands on Heads is $\frac{1}{4}$ .

(b)

The sample space such that at least one toss lands on heads is:

S₂ = {HHH, HHT, HTH, THH, HTT, THT, TTH} = 7 outcomes

The probability that all three tosses land on heads given that at least one toss lands on heads is,

P (3 Heads | At least 1 Heads) $=\frac{P(3\ Heads\ \cap\ At\ least\ 1\ Heads)}{P( At\ least\ 1\ Heads)}$

$=\frac{\frac{1}{7} }{\frac{7}{8} } \\=\frac{1}{8}\times \frac{8}{7}\\ =\frac{1}{7}$

Thus, the probability that all three tosses land on heads given that at least one toss lands on heads is $\frac{1}{7}$ .

4 0

3 years ago