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ad-work [718]
3 years ago
15

IF ANSWERED WITHIN 10 MINUTES I WILL GIVE BRAINLEST!!

Mathematics
1 answer:
vivado [14]3 years ago
6 0

Answer:

...0

Step-by-step explanation:

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Which expression is equivalent to<br> (5^-2)(5^-1)<br> A. -1/125<br> B. -1/5<br> C. 1/125<br> D. 1/5
n200080 [17]

Answer:

1/125

Step-by-step explanation:

(5^-2)(5^-1) = 5^-3=1/5^3=1/125

3 0
3 years ago
1. Solve for w in the equation W/5 = 25<br> A.W = 5<br> B.W = 125<br> C. W = 30<br> D.W = 20
vekshin1

Answer: <em>w = 125</em>

Explanation: Since <em>w</em> is being divided by 5, to solve for <em>w</em>,

multiply both sides of the equation by 5.

On the left side, the 5's will cancel

and on the right side, 25(5) is 125.

So <em>w = 125</em>.

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<u>Please do not do this problem in your head.</u>

Show the work that it takes to get <em>w</em> by itself.

3 0
3 years ago
What is 3/8 equal to in decimals..?
MrRissso [65]

Answer: 0.375

Step-by-step explanation:

Hey there! If you have any questions feel free to leave them in the comments below.

To find the answer you would divide the numerator by the denominator. \frac{3}{8} would be equal to 0.375

~I hope I helped you :)~

3 0
3 years ago
Read 2 more answers
Help I don’t get it
vlada-n [284]

Answer:

143

Step-by-step explanation:

Your equation to find x is:

140+146/2 = 143

3 0
2 years ago
Two accounts earn simple interest. The balance y (in dollars) of Account A after x years can be modeled by y=10x 500. Account B
12345 [234]
In an installment loan, a lender loans a borrower a principal amount P, on which the borrower will pay a yearly interest rate of i (as a fraction, e.g. a rate of 6% would correspond to i=0.06) for n years. The borrower pays a fixed amount M to the lender q times per year. At the end of the n years, the last payment by the borrower pays off the loan.

After k payments, the amount A still owed is

<span>A = P(1+[i/q])k - Mq([1+(i/q)]k-1)/i, = (P-Mq/i)(1+[i/q])k + Mq/i. </span>The amount of the fixed payment is determined by<span>M = Pi/[q(1-[1+(i/q)]-nq)]. </span>The amount of principal that can be paid off in n years is<span>P = M(1-[1+(i/q)]-nq)q/i. </span>The number of years needed to pay off the loan isn = -log(1-[Pi/(Mq)])/(q log[1+(i/q)]). The total amount paid by the borrower is Mnq, and the total amount of interest paid is<span>I = Mnq - P.</span>
3 0
2 years ago
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