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OleMash [197]
3 years ago
12

A birthday candle costs $0.84. How much do 6 birthday candles cost?

Mathematics
2 answers:
spin [16.1K]3 years ago
4 0

Answer:

$5.04

Step-by-step explanation:

Take the cost of one candle and multiply the number of candles desired

6 *.84 =5.04

Aleksandr [31]3 years ago
3 0

Answer: $5.04

Step-by-step explanation:

If one candle costs 0.84, and you need 6 then you multiply 0.84 x 6=5.04.

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Answer:

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}

Hence, ption B is true.

Step-by-step explanation:

Given the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

solving the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

as

\sqrt{x^2y^3}=xy\sqrt{y}

2\sqrt{x^3y^4}=2xy^2\sqrt{x}

so the expression becomes

\:\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}

Group like terms

                                        =2xy^2\sqrt{x}+xy\sqrt{y}+xy\sqrt{y}

Add similar elements

                                        =2xy^2\sqrt{x}+2xy\sqrt{y}

Therefore, we conclude that:

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}

Hence, option B is true.

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