If <span>I
understand the question correct, the hockey season ticket holder paid
$72.48 for all of the tickets at once, and then $6.00 for each game
thereafter. The second person pays $18.08 for a ticket per game.
So then let g = the number of games. The problem can be written as a system of equations:
Person 1 = 72.48 + 6g
Person 2 = 18.08g
We are looking for when the number of games for both are the same. To do
this, just set them equal to each other and solve for g.
72.48 + 6g = 18.08g
Subtract 6g:
72.48 = 12.08g
Divide by 12.08:
g = 6
So after 6 games, the two would have paid the same price.
</span>
The square of an odd number:
We're to conjecture, not do algebra, apparently. 1²=1, 3²=9, 5²=25, 7²=49, ...
We conjecture the square of an odd number is odd.
The product of two evens and an odd:
Again, we'll run some examples.
(2)(2)(1)=4
(2)(4)(3)=24
(4)(6)(5) =120
(4)(8)(1)=32
Conjecture: The product of two evens and an odd is a multiple of 4
Counterexample: The product of two fractions is never an integer
How about
3/4 × 4/3 = 1
Answer:
inches
Step-by-step explanation:
Let the width be x.
Length =
Perimeter = Length + Length + Breadth + Breadth
Perimeter =
Subtract 12 from both sides:
Divide both sides by 4:
(Width)
Length = inches.
3. retangle
4. parallelogram
Second and fourth are rational number