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3 years ago

what is the equation of the following line? Be sure to scroll down first to see all answer options. ( -1/2, -3) ( 0, 0)

Mathematics

2 answers:

dlinn [17]3 years ago

5 0

I got y = 1/5x fo this one.............

pychu [463]3 years ago

4 0

Y=1/5x should be the right answer

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ALGEBRAIC PROOF!!!! PLS HELP!!! The area of a rectangular blanket is 20 square feet. The blanket's length is (2x + 1) ft and the

Fynjy0 [20]

Answer:

Length: 5 ft; width: 4 ft.

Step-by-step explanation:

A = LW formula for area of rectangle

(2x + 1)(2x) = 20 substitute length, width, and area into formula

4x² + 2x - 20 = 0 use the distributive property to multiply out left side

2x² + x - 10 = 0 divide both sides of equation by 2

(2x + 5)(x - 2) = 0 factor out trinomial

2x + 5 = 0 or x - 2 = 0 use zero product rule to solve for x

2x = -5 or x = 2 subtract 5 from both sides; add 2 to both sides

x = -5/2 or x = 2

We discard x = -5/2 since it would give negative length and width, and the length and width cannot be negative.

Length: 2x + 1 = 2(2) + 1 = 5

Width: 2x = 2(2) = 4

Length: 5 ft; width: 4 ft.

7 0

3 years ago

What is the function

Mrrafil [7]

You have the answer correct

4 0

3 years ago

PLEASE HELP GEOMETRY<br> EXPLAIN PLEASE

Anastaziya [24]

I believe the answer is the first one because it’s congruent

3 0

3 years ago

Evaluate the following expressions, and justify your answers.<br> WhatPower7(49)

MaRussiya [10]

Answer:

whatpower7(49) = 2

Step-by-step explanation:

given data

WhatPower7(49)

to find out

Evaluate the expressions WhatPower7(49)

solution

as we know that whatpower mean exponent of equation so we get by given equation

we know whatpower7(49) = 2

because

we know that 7 × 7 = 49

so that 7² = 49

so that the exponent is here 2 for 7 that become 49

so correct answer is 2

6 0

3 years ago

Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]

alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

$\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]$

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)² = 3√6

Therefore, the unit vector is

$\frac{[7,2,-1]}{3\sqrt{6} }$

[ $\frac{7}{3\sqrt{6} }$ , $\frac{2}{3\sqrt{6} }$ , $\frac{-1}{3\sqrt{6} }$ ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ $\frac{-7}{3\sqrt{6} }$ , $\frac{-2}{3\sqrt{6} }$ , $\frac{1}{3\sqrt{6} }$ ]

In conclusion, the two unit vectors are;

[ $\frac{7}{3\sqrt{6} }$ , $\frac{2}{3\sqrt{6} }$ , $\frac{-1}{3\sqrt{6} }$ ]

and

[ $\frac{-7}{3\sqrt{6} }$ , $\frac{-2}{3\sqrt{6} }$ , $\frac{1}{3\sqrt{6} }$ ]

<em>Hope this helps!</em>

7 0

3 years ago