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Vlada [557]
3 years ago
8

I need help please ASAP

Mathematics
1 answer:
strojnjashka [21]3 years ago
6 0

Answer:

1. 2, 3

2. 3, 7

3. 5, 2

4. 16, -10

Step-by-step explanation:

1. y=y       x+1=y=4x-5         x+1=4x-5           3x=6   x=2    y=3

2. x+y = 10      y=10-x     y=y    3x-2=10-x    4x=12 x=3  y=7

3. y=7-x   x-(7-x)=3    x-7+x=3     2x=10    x=5   y=2

4. y=6-x      2x+(6-x)=10      x+6=10    x=16    y=-10

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Geometry ! No links please
DENIUS [597]

The Answer Is CD=5

AB/BC=2

2=BE/CD

2/1=10/X

2/1=10/5

2=2

6 0
3 years ago
Help like rn. Like rn please I will mark brainiest but pls help.
Naya [18.7K]

Answer:

90

and

20

i think so ye

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A right triangle is removed from a rectangle to create the shaded region shown below. Find the area of the shaded region. Be sur
Mashcka [7]
The sides of a right triangle are
a=8-5=3
\\ b=6-4=2
\\
\\A=A_{rectangle}-A_{triangle}=8\times 6-  \frac{ab}{2} =48-\frac{3\times2}{2}=48-3=45
7 0
3 years ago
Read 2 more answers
Find the Y-coordinate of point P that lies 1/3 along segment RS, where R (-7, -2) and S (2, 4).
QveST [7]

Solution:

Given that the point P lies 1/3 along the segment RS as shown below:

To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have

\begin{gathered} RP:PS \\ \Rightarrow\frac{1}{3}:\frac{2}{3} \\ thus,\text{ we have} \\ 1:2 \end{gathered}

Using the section formula expressed as

[\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}]

In this case,

\begin{gathered} m=1 \\ n=2 \end{gathered}

where

\begin{gathered} x_1=-7 \\ y_1=-2 \\ x_2=2 \\ y_2=4 \end{gathered}

Thus, by substitution, we have

\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}

Hence, the y-coordinate of the point P is

0

8 0
1 year ago
Estimate how long it will take to complete the
drek231 [11]

Answer:

14

Step-by-step explanation:

It's just that simple man.

5 0
3 years ago
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