A.) <span>Scalene Triangle has no Lines of S</span>ymmetry
B.) <span>A </span>Square<span> (4 sides) </span><span>has </span>4 Lines of Symmetry
C.) <span>A </span>Regular Hexagon<span> (6 sides) </span>has 6 Lines of Symmetry
D.) <span>A </span>Regular Octagon<span> (8 sides) </span><span>has </span>8 Lines of Symmetry
Call red as X then X/Green =5/16 => green = 16X/5.
six times the number of reds exceeded the number of green by 112 => 6X-16X/5=112 => 14X/5=112 => X= 40 => reds:40 => green = 128
Answer:
the pictures are blocked
Step-by-step explanation:
Answer:
Pr(B) = 0.69
Pr(J/B) = 0.35
Pr(J∩B) = 0.14
Pr(G/J') = 0.66
Pr(G) = 0.31
Step-by-step explanation:
Applying,
Pr = possible outcome (a)/Total outcome(t)
(1) Pr(B) = a/t............ Equation 1
From the diagram
Given: a = 220+65+35 = 320, t = 220+65+35+145 = 465
Substitute these values into equation 1
Pr(B) = 320/465
Pr(B) = 0.69
(2) Pr(J/B) = (35+65)/(220+65)
Pr(J/B) = 100/285
Pr(J/B) = 0.35
(3) Pr(J∩B) = 65/465
Pr(J∩B) = 0.14
(4) Pr(G/J') = 145/220
Pr(G/J') = 0.66
(5) Pr(G) = 145/465
Pr(G) = 0.31
Answer:
70%
Step-by-step explanation:
