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kompoz [17]
3 years ago
8

Which paper folding method can be used to form parallel lines?

Mathematics
1 answer:
lubasha [3.4K]3 years ago
8 0

by folding at right angles

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Simplfiy the expression -5+i/2i
Elodia [21]
-5i/2i. is the answer because all you have to do is add the -5 and the i.
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3 years ago
Which is the graph of the sequence defined by the function f(x + 1) = Three-fifthsf(x) when the first term in the sequence is 37
nadezda [96]

Answer: On a coordinate plane, 4 points are plotted. The points are (1, 375), (2, 225), (3, 135), (4, 81).

Step-by-step explanation:

We have the relation:

f(x + 1) = (3/5)*f(x)

such that the first term is 375

Then:

f(1) = 375.

Using the above relation, we have that:

f(1 + 1) = f(2) = (3/5)*f(1) = (3/5)*375 = 225

Then we have the pair (2, 225)

The next term is:

f(2 + 1) = f(3) = (3/5)*f(2) = (3/5)*225 = 135

Then we have the pair (3, 135)

the next term is:

f(3 + 1) = f(4) = (3/5)*f(3) = (3/5)*135 = 81

Then we have the pair (3, 81)

Then the correct option is the first one; On a coordinate plane, 4 points are plotted. The points are (1, 375), (2, 225), (3, 135), (4, 81).

9 0
2 years ago
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Factor the expression <br> 5x^2 -22x -15
Murljashka [212]
5x^2-22x-15=5x^2\underbrace{-25x+3x}_{-22x}-15\\\\=(5x^2-25x)+(3x-15)=5x(x-5)+3(x-5)\\\\=\boxed{(x-5)(5x+3)}

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What Val are restricted from the domain of
djverab [1.8K]

<u>Given</u>:

The given expression is \frac{\left(4 x^{2}-4 x+1\right)}{(2 x-1)^{2}}

We need to determine the values for which the domain is restricted.

<u>Restricted values:</u>

Let us determine the values restricted from the domain.

To determine the restricted values from the domain, let us set the denominator the function not equal to zero.

Thus, we have;

(2x-1)^2\neq 0

Taking square root on both sides, we get;

2x-1\neq 0

     2x\neq 1

      x\neq \frac{1}{2}

Thus, the restricted value from the domain is x\neq \frac{1}{2}

Hence, Option A is the correct answer.

7 0
3 years ago
Someone please help me with this problem
tamaranim1 [39]

Answer:

sorry my cumputer is not working

Step-by-step explanation:

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