<h2>
Answer:</h2>
<h2>
Step-by-step explanation:</h2>
A circle is a curve made up of all the points that are the same distance from the center. In this problem, we are asked to find the area of the sector. A sector is a region of a circle between two radii. Suppose you have a central angle 
degrees, the sector can be found as:
We know:
So:
Answer:Sure
Step-by-step explanation:Me too
Numerator:
the product of 5 and the sum of x and y = 5(x + y)
Denominator:
the product of negative 8 and x = -8x
So the quotient:
5(x + y)
------------
- 8x
Answer is the second one.
5(x + y)
------------
- 8x
Answer:
1) ∠A=84°
2) ∠C=20°
Step-by-step explanation:
1)
First, find ∠C:
<em>(I'm assuming the exterior angle of 126° makes a straight line with ∠C)</em>
The angles on a straight line always add up to 180. Therefore:
∠C+126=180
∠C=180-126
∠C=54
Then find ∠B:
We also know that all the angles in a triangle add up to 180. Therefore:
∠A+∠B+∠C=180
∠A+∠B+54=180
∠A+∠B=126
<em>(we know ∠A=2(∠B))</em>
2(∠B)+∠B=126
3(∠B)=126
∠B=42
Now, find ∠A:
∠A=2(∠B)
∠A=2(42)
∠A=84°
2)
First, find ∠B:
<em>(Again, I'm assuming the exterior angle of 100° makes a straight line with ∠B)</em>
The angles on a straight line always add up to 180. Therefore:
∠B+100=180
∠B=180-100
∠B=80
Then find ∠A:
We also know that all the angles in a triangle add up to 180. Therefore:
∠A+∠B+∠C=180
∠A+80+∠C=180
∠A+∠C=100
<em>(we know ∠A=4(∠C))</em>
4(∠C)+∠C=100
5(∠C)=100
∠C=20°
