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4 years ago

To be a vertical angle, the angles have to be next to each other. A. True B. False

Mathematics

1 answer:

12345 [234]4 years ago

3 0

False, vertical angles are not next to each other but opposite of each other

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Solve by the method of your choice 6x-2y= 16, 5x+y=24

Soloha48 [4]

6x-2y=16
(5x+y=24)*2
__________

6x-2y=16
10+2y=48 Add the equations”+”
—-
16x=64
X=4
So y=1

6 0

3 years ago

What key features can be identified from graphs of polynomials of higher degrees?

devlian [24]

Polynomials are algebraic expressions that contain more than two terms. AN example would be: f(x) = x^3 + x^2 + x +1. This equation contains three terms, with the 3rd degree as its highest term. It also means that the graph passed three x-intercepts. This depends in the highest degree. So, the first thing you do is plot the intercepts because for sure, the graph will pass there.

Hope this helps :)

4 0

4 years ago

How do you solve -9/14 + 2/7 showing work

lys-0071 [83]

-9/14 4/14 now you have the same denominator so you can add
-9 + 4 = -5

-5/14

4 0

3 years ago

The graphs below have the same shape. What is the equation of the blue graph?

Dvinal [7]

For this case we have that by definition of vertical translations of functions, it is fulfilled:

Assume $k> 0$ :

To graph $y = f (x) + k$ , the graph k units is moved up.

To graph $y = f (x) -k$ , the graph moves k units down.

In the figure it is observed that:

The original function is $G (x) = x ^ 2$ , the function was moved 4 units down. So, the new function is:

$F (x) = x ^ 2-4$

Answer:

Option B

7 0

4 years ago

Read 2 more answers

The chorus has six sopranos and eight baritones. in how many ways can the director choose a quartet that contains at least one s

adell [148]

If you have six sopranos and eight baritones, you have fourteen musicians in total.
The number of possible quartets that you can get with 14 musician is:
$14C4= \frac{14!}{4!(14-4)!}$
$14C4= \frac{14!}{(4!)(10!)}$
$14C4=1001$

Now, the number of possible quartets without a soprano that you can have is:
$8C4= \frac{8!}{4!(8-4)!}$
$8C4= \frac{8!}{(4!)(4!)}$
$8C4=70$

Therefore, the number of quarters that contains at list one soprano will be the number of possible quarters minus the number of quarters without a soprano:
$1001-70=931$
We can conclude that the director can choose a quarter which contains at least one soprano in 931 ways.

4 0

4 years ago