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Airida [17]
3 years ago
10

Look at attachment for the question

Mathematics
2 answers:
timurjin [86]3 years ago
5 0

Answer:

C

Step-by-step explanation:

For two shapes to be similar they must have a set ratio. The only one that does have a set ratio is Y.

So the answer is C

The ratio is 1 : 2

1 * 2 = 2 = w = Yw (the width for rect y)

2 * 2 = 4 = l = Yl (the length for rect Y)

Eduardwww [97]3 years ago
5 0
C have a blessed fulfilled day
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Can someone help me
FromTheMoon [43]
BC is 8.7 
CA is 20
hope this helps
6 0
3 years ago
Suppose that y varies directly with x<br> and y3 when x = 9. What is y<br> when x = 18?<br> y = [?]
exis [7]

Answer:

y=6

Step-by-step explanation:

y=kx

3=9k

k=3/9

k=1/3

y=kx

y=1/3 × 18

y=6

8 0
2 years ago
Please help me with this problem. How do I find x?
inysia [295]
Assuming that is 2 right triangles sharing a side
height^2 = 20^2 -7^2
height^2 = 400 - 49
height^2 = 351
height = <span> <span> <span> 18.7349939952 </span> </span> </span>
x^2 = 24^2 - <span>18.7349939952^2
x^2 = 576 -351
x^2 = 225
x = 15

</span>
7 0
3 years ago
How many five-card hands (drawn from a standard deck) contain exactly three fives? (A five-card hand is any set of five differen
VashaNatasha [74]

Answer:

4512.

Step-by-step explanation:

We are asked to find the number of five-card hands (drawn from a standard deck) that contain exactly three fives.

The number of ways, in which 3 fives can be picked out of 4 available fives would be 4C3. The number of ways in which 2 non-five cards can be picked out of the 48 available non-five cards would be 48C2.

4C3=\frac{4!}{3!(4-3)!}=\frac{4*3!}{3!*1}=4

48C2=\frac{48!}{2!(48-2)!}=\frac{48*47*46!}{2*1*46!}=24*47=1128

We can choose exactly three fives from five-card hands in 4C3*48C3 ways.

4C3*48C3=4*1128=4512

Therefore, 4512 five card hands contain exactly three fives.

4 0
3 years ago
Twice a number,n, increased by 7 is equal to 19
rosijanka [135]
I think the answer is 6
6 0
3 years ago
Read 2 more answers
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