8x^3y^4-22x^5y^6 gcf
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Answer:
the ball reaches a height of 64 feet after 2 sec.
The ball is in the air 4 sec.
Step-by-step explanation:
The ball is following the path of a parabola. The maximum height is at the vertex of the parabola.
Let (h, k) be the vertex. h will be the time it takes to reach the maximum height, and k will be that height.
y =
h = -b/2a = 64/(-2)(-16) = 64/32 = 2
k = -16(2)^2 + 64(2)
-16(4) + 128
- 64 + 128 = 64
V: (2, 64)
So the ball reaches a height of 64 feet after 2 sec.
Let = 0 (0 is the height when the balls hits the ground)
-16t(t - 4) = 0
t = 0 or t = 4
The ball is in the air 4 sec.