For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
<h3>
Integers divisible by 3</h3>
The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.
<h3>Proof for the divisibility</h3>
111 = 1 + 1 + 1 = 3 (the sum is multiple of 3 = 3 x 1) (111/3 = 37)
222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2) (222/3 = 74)
213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2) (213/3 = 71)
27 = 2 + 7 = 9 (the sum is multiple of 3 = 3 x 3) (27/3 = 9)
Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
Learn more about divisibility here: brainly.com/question/9462805
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Answer:
well heck i cant see the picuter
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
Think about the question, you can't say that i am wong.
Answer:
(or 6.25)
Step-by-step explanation:
Let's do a simple square problem to see the relationship between the elements of the resulting equation...
As you see, the number of 'x' (6) is the double of the numeric part of the binomial expression (3), while the numeric-only part (9) is the square of the numeric part of the binomial expression (3).
So, if we look at the formula from the problem, we see the the number of 'x' is 5. To obtain the C value, we need to divide the 5 by 2... then get the square value of the result.
(or 6.25)
Of means multiplication. So the question is 1/3 X 1 1/2. First make 1 1/2 improper: 3/2. Then multiply the numerators (top numbers) and denominaters (bottom numbers): 1x3=3, 3x2=6, =3/6. Now simplify 3/6=1/2. Then multiply that by 2, since he used 2 pieces: 1/2x2=1. John used 1 meter :)
