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3 years ago

Which function represents the graph y=10(4)^x ?

Mathematics

2 answers:

Alex3 years ago

8 0

Answer:

Function g

Step-by-step explanation:

In order to solve this, you just have to calculate the intersect with the Y axis, to do this you just need to insert into the function 0 as the value of X:

y=10(4)^x

y=10(4)^0

y=10(1)

y=10

So the intersect with the Y axis is 10. The only graph that has the intersect with the Y axis at 10 is graph g, so that one would be the answer.

inn [45]3 years ago

5 0

The answer is function g

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Two isosceles triangles are shown above. If b = 180-4a and a=35, What is the value of c?

Ymorist [56]

Answer:

a=35 given

b=40

c=110

I couldn't complete see c. Please look at the picture to see what I assumed it to be.

Step-by-step explanation:

Hmmm... I guess a and b are not vertical.

We are given b=180-4a and a=35 so b=180-4(35)=180-140=40.

So b=40.

Isosceles triangles always have congruent base angles. So let's call both of the base angles in the bottom triangle x.

That means x+x+40=180.

We need to solve this for x.

Combine like terms:

2x+40=180

Subtract 40 on both sides:

2x=140

Divide both sides by 2:

x=140/2

Simplify:

x=70

So I'm assuming that c and it's adjacent angle are sitting on a straightedge together which means 70+c=180.

70+c=180

Subtract 70 on both sides:

c=180-70

Simplify:

c=110

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Step-by-step explanation:

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1 year ago

What is the projection of (4,4) onto (3,1)?

Ostrovityanka [42]

Let's define the vectors:
U = (4.4)
V = (3.1)
The projection of U into V is proportional to V
The way to calculate it is the following:
Proy v U = [(U.V) / | V | ^ 2] V
Where U.V is the point product of the vectors, | V | ^ 2 is the magnitude of the vector V squared and all that operation by V which is the vector.
We have then:
U.V Product:
U.V = (4,4) * (3,1)
U.V = 4 * 3 + 4 * 1
U.V = 12 + 4
U.V = 16
Magnitude of vector V:
lVl = root ((3) ^ 2 + (1) ^ 2)
lVl = root (9 + 1)
lVl = root (10)
Substituting in the formula we have:
Proy v U = [(16) / (root (10)) ^ 2] (3, 1)
Proy v U = [16/10] (3, 1)
Proy v U = [1.6] (3, 1)
Proy v U = [1.6] (3, 1)
Proy v U = (4.8, 1.6)

Answer:
the projection of (4,4) onto (3,1) is:
Proy v U = (4.8, 1.6)

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3 years ago