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Olegator [25]
3 years ago
10

Do any of you guys know how to solve this

Mathematics
1 answer:
Alex17521 [72]3 years ago
5 0
<span><span><span><span>2<span>x^3</span></span>+<span>6x</span></span>+152
</span><span>x+4</span></span><span>=<span><span><span><span>2<span>x^3</span></span>+<span>6x</span></span>+152
</span><span>x+4</span></span></span><span>=<span><span><span>2<span>(<span>x+4</span>)</span></span><span>(<span><span><span>x^2</span>−<span>4x</span></span>+19</span>)
</span></span><span>x+4</span></span></span><span>=<span><span><span>2<span>x^2</span></span>−<span>8x</span></span>+<span>38= is the answer</span></span></span>
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Step-by-step explanation:

Given the expression, (3y ^ 6 + 4)  (9y ^ {12} - 12y ^ 6 + 16), we want to know which sign placed in between the two polynomial will produce a binomial.

Using a plus (+) sign to check:

= (3y ^ 6 + 4) + (9y ^ {12} - 12y ^ 6 + 16)\\=  (3y ^ 6 + 4) + (9y ^ {12} - 12y ^ 6 + 16)\\collect \ like \ terms\\= 9y^{12} +3y^6 - 12y^6 + 16+ 4\\= 9y^{12} - 9y^6 + 20\\

From the gotten value, it can be seen that the resulting answer produces 3 terms, showing that it results in a trinomial instead of binomial.

Using a plus (-) sign to check:

= (3y ^ 6 + 4) - (9y ^ {12} - 12y ^ 6 + 16)\\=  3y ^ 6 + 4 - 9y ^ {12} + 12y ^ 6 - 16\\collect \ like \ terms\\= -9y^{12} +3y^6 +12y^6 + 4-16\\= -9y^{12} +15y^6 -12\\

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Hope this helped!
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