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soldier1979 [14.2K]
4 years ago
6

¿que tipos de compuestos son los que tienen como elemento central carbono combinado con oxigeno e hidrógeno?

Chemistry
1 answer:
Alexxandr [17]4 years ago
3 0
Cuando se combina con oxígeno e hidrógeno, el carbono puede formar muchos grupos de compuestos biológicos importantes que incluyen carbohidratos (azúcares), lignanos (importantes en las plantas), quitinas (el componente principal de las paredes celulares de los hongos, los exoesqueletos de los artrópodos), alcoholes, lípidos y grasas (triglicéridos) y carotenoides.
(Lo busqué) espero que esto ayude:)
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A baby weighs 7 pounds, 4 ounces at birth and 7 pounds, I ounce at discharge. What percent of weight did the baby lose
Aloiza [94]

Answer:

2.6%

Explanation:

As, 1 ounce (oz) =  0.0625 pounds (lb)

Therefore, weight of baby at discharge = 7 lb,1 oz = 7+0.0625 lb = 7.0625 lb

Since, 1 oz =  0.0625 lb

⇒ 4 oz = 4×0.0625 = 0.25 lb

Therefore, weight of baby at birth = 7 lb,4 oz = 7+0.25 lb = 7.25 lb

The <u>amount of weight lost</u> is equal to the difference of weight of the baby at birth and discharge.

Therefore, <u>weight lost</u> = 7.25 lb - 7.0625 lb = <u>0.1875 lb</u>

Now, the <u>percentage of weight lost</u> by the baby is given by the amount of weight lost divided by the weight of the baby at birth.

Therefore, <u>the percentage of weight los</u>t = weight lost ÷ weight at birth = 0.1875 lb ÷ 7.25 lb × 100 = <u>2.6% </u>

6 0
4 years ago
Name each of the following chemistry structures (picture) plz
Triss [41]

Answer:

(a) 3-ethylpentane (because the longest chain is 5 carbon atoms, and ethyl is positioned at the 3rd carbon atom)

(b) 1, 2-dimethylbutane (because two methyl is positioned at the 2nd and 3rd carbon atom)

(c) 3, 4-dimethylhexane (the longest chain here is 6 carbon atoms, and two methyl is positioned at the 3rd and 4rd carbon atom)

(d) 3-methyl 4-ethylhexane ( the longest chain is 6 carbon atoms, one methyl is positioned at the 3rd carbon atom while one ethyl is positioned at the 4rd carbon atom)

(e) and (f) are similar to the question before... and I dunno how to (g) and (h) cuz I haven't learned it

Hope that you are able to answer the rest!!

4 0
4 years ago
A block of material has a volume of 2m^3. It has a mass of 1 ×10^4 kg. Calculate the density of the material sample and express
Ivenika [448]

Answer:

The answer to your question is: density = 5 g/cm³

Explanation:

Data

Volume = v = 2 m³

mass = m = 1 x 10⁴ kg

Density = d = ? g/cm³

Formula

density = mass/volume

Volume

                          1 m³ -------------------  1 000 000 cm³

                          2 m³ ------------------     x

                          x = (2 x 1 000 000) / 1

                         x = 2 000 000 cm³

Mass

                          1 kg ------------------   1000 g

                         1 x 10⁴ kg ------------    x

                         x = (1 x 10⁴ x 1000) / 1

                         x = 10 000 000 g

density = (10 000 000) / 2 000 000

density = 5 g/cm³

5 0
3 years ago
00000044m<br> 300000km/s <br> Both in scientific notation
cupoosta [38]

Answer:

4.4 × 10^-7

3 × 10^5

Explanation:

scmack me wit dat brainliest

5 0
3 years ago
How many moles of tin atoms are there in 250 grams of tin?
joja [24]

250gTi x (1mol/47.87 [molar mass]) =5.22247 moles

4 0
3 years ago
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