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Agata [3.3K]
3 years ago
14

You are given a sample of a Group II metal chloride, but the identity of the metal is unknown. Knowing that all Group II metal c

hloride compounds have the general formula, MCI2 and that the percentage of chlorine in the compound is 34.1%, what is the identity of the unknown substance?​
Chemistry
1 answer:
topjm [15]3 years ago
4 0

Answer:

The identity of unknown substance is Barium.

Explanation:

The given compound has a formula of MCl2. And the percentage of chlorine in this compound is said to be 34.1 %. But, we know that the mass of chlorine in this compound is, 35.5*2 = 71 g

Therefore, if we let x be the total mass of the compound, then:

34.1% of x = 71 g

(0.341)x = 71 g

x = 71 g/0.341

x = 208.2 g

Hence, the mass of other atom M, must be:

M = x - 71 g

M = 208.2 g - 71 g

M = 137.2 g

Now, we look into periodic table in group II. We find that the element is Barium with atomic mass of 137 g.

<u>The identity of unknown substance is Barium.</u>

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What’s the IUPAC name
hichkok12 [17]

Answer:

Methyl pentanoate.

Explanation:

Hello there!

In this case, according to the given information, we can see the correct structure will be:

                             O

                              ||

CH3CH2CH2CH2COCH3

Which matches with the structure of an ester due to the -COO- functional group. In such a case, the first part of the name is in function of the right side of the ester, in this case, methyl, followed by the left side, pentanoate, as it has five carbon atoms and is an ester (similar to an inorganic salt, but organic) and therefore, the name will be methyl pentanoate.

Regards!

5 0
3 years ago
If crystal growth does not start on its own after the solution in the flask returns to room temperature, identify the best ways
deff fn [24]

Answer: The best way to promote the process are:

--> Add a bit of solid as a seed crystal.

--> Scratch the bottom of the flask gently with a stirring rod.

Explanation:

A crystal growth is seen is SUPERSATURATED solutions which contains more solute than it can normally dissolve at that given temperature. It is usually very UNSTABLE and capable of releasing the excess solute if disturbed, either by shaking or seeding with a tiny crystals.

Crystallization can be used for the separation of two salts with different solubilities as well as for purification of a soluble salt that contains insoluble solid impurities. Recrystallization improves the validity of the process. Crystallization can be initiated by:

--> Scratching the bottom of the flask gently with a stirring rod: scratching initiates crystallization by providing energy from the high-frequency vibrations.

--> Adding a bit of solid as a seed crystal: Seed crystals create a nucleation site where crystals can begin growth.

7 0
3 years ago
What contribution to atomic theory resulted from albert einstein’s work?
Hatshy [7]

Answer:

Albert Einstein is perhaps most famous for introducing the world to the equation E=mc2. In essence, he discovered that energy and mass are interchangeable, setting the stage for nuclear power—and atomic weapons. His part in the drama of nuclear war may have ended there if not for a simple refrigerator.

Explanation:

Albert Einstein is perhaps most famous for introducing the world to the equation E=mc2. In essence, he discovered that energy and mass are interchangeable, setting the stage for nuclear power—and atomic weapons. His part in the drama of nuclear war may have ended there if not for a simple refrigerator.

8 0
3 years ago
Read 2 more answers
PLEASE ANSWER THIS QUESTION FAST :(
kramer
Mol sulfuric acid = 19 g * (1 mol) / (98.1 g) = 0.19367 mol
mol H2O = 0.19367 mol H2SO4 * (2 H2O) / (1 H2SO4)
                = 0.387359 mol H2O
grams H2O = 0.387359 mol H2O * (18 g)/(1 mol)
                     = 6.97 g
The answer is 7.0 grams of water
6 0
3 years ago
At 25 °C, what is the hydroxide ion concentration, [OH−] , in an aqueous solution with a hydrogen ion concentration of [H+]=4.8×
algol [13]

[OH⁻]= 1 x 10⁻¹⁴ : 4.8 x 10⁻⁴ = 2.083 x 10⁻¹¹

3 0
1 year ago
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