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adoni [48]
3 years ago
14

Please help me on this ?!?!?!

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
7 0
show the picture of the problem not just the answers and might be able to help you.
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Let f be the function that determines the area of a circle (in square cm) that has a radius of r cm. That is, f ( r ) represents
Zepler [3.9K]

Answer:

(a)f(4) square cm.

(b)f(10.91)-f(10.9) Square centimeter.

Step-by-step explanation:

f(r)=the area of a circle (in square cm) that has a radius of r cm.

(a)Area (in square cm) of a circle whose radius is 4 cm.

Since r=4cm

Area of the circle = f(4) square cm.

(b) When the radius of the increases from 10.9 to 10.91 cm.

  • Area of the circle with a radius of 10.91 = f(10.91) square cm.
  • Area of the circle with a radius of 10.9 = f(10.9) square cm.

Change in the Area = f(10.91)-f(10.9) Square centimeter.

4 0
4 years ago
3.
bezimeni [28]

3/2 is the answer

OPTION (D)

7 0
4 years ago
Solve the system of equations x + y = 0 and x + 9y= -48 by combing the eqatuons
lidiya [134]

Answer:

x = 6

y = -6

Step-by-step explanation:

x + y = 0 (Multiply by -1)

x + 9y= -48

-x - y = 0

x + 9y= -48

8y = -48

y = -6

x + y = 0

x - 6 = 0

x = 6

7 0
3 years ago
A party planner is going to use an arch of balloons for a parade of recent graduates. The estimated curve the
lesya [120]

Answer:

Option (4)

Step-by-step explanation:

Party planner has used an arc of balloons for the parade.

This arc starts from x = 0 along the ground and f(x) defines the height of the arch.

From the table attached, it is clear that at x = 4 maximum height of the arch is 9.6 feet.

Therefore, clearance space below the arc is 9.6 feet which is greater than 9 feet, minimum height required for the clearance of the parade.

Option (4) will be the answer.

8 0
3 years ago
The daily water consumption for an Ohio community is normally distributed with a mean consumption of 722,500 gallons and a stand
Allisa [31]

Answer:

0.0060

Step-by-step explanation:

The z-score is given by

<em>z = (866,475-722,500)/57,429 = 2.51 </em>

The probability is given by the area under the Normal curve N(0,1) to the <em>right</em> of 2.51

In <em>Excel </em> this value is found with the formula

=1-NORMDIST(2.51,0,1,1)

and in <em>OpenOffice Calc </em>

=1-NORMDIST(2.51;0;1;1)

<em> (NORMDIST(2.51;0;1;1) gives the area to the left of 2.51, so 1-NORMDIST(2.51;0;1;1) gives the area to the right of 2.51) </em>

and equals 0.0060

8 0
3 years ago
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