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4 years ago

Which angle is NOT congruent to angle 1?

Mathematics

1 answer:

Leni [432]4 years ago

6 0

Those angles would be 2, 4, 6, and 8

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What is 4/7 raised to the power of negative 1 as a rational number

Harlamova29_29 [7]

Answer:

7/4

Step-by-step explanation:

(4/7)^-1

We know a^-b = 1/a^b

1/ (4/7)^1

7/4

5 0

3 years ago

Read 2 more answers

Which values have exactly 2 significant figures? Check all that apply.

JulijaS [17]

ANSWER

Options B, C and D have exactly 2 significant figures.

<u>EXPLANATION</u>

To see whether the numbers have exactly 2 significant figures, round all to 2 significant figures. The ones that remains the same have exactly 2 significant figures.

$302\approx 300$ yards to 2.s.f

$980\approx 980$ gallons to 2.s.f

$1200\approx 1200$ feet to 2.s.f

$84\approx 84$ litters to 2.s.f\

$6,040\approx 6,000$ meters to 2.s.f

8 0

4 years ago

Read 2 more answers

A fisherman can tow upstream at 4 mph and downstream at 6 mph. He started rowing upstream until he got tired and then rowed down

telo118 [61]

He went upstream 3 hours and downstream two. 4x3=12 6x2=12

He went 24 miles.

5 0

3 years ago

What is the range of the function shown in the graph?<br>

Vika [28.1K]

Answer:

y ≥ 2

Step-by-step explanation:

Range is the y-axis, so we have to look at the graph to find what numbers the line hits.

The line starts at y = 2 and goes up forever (the arrow indicates this), so that means that this line hits all y-values above 2.

Therefore the range is any y-value 2 or higher, so the answer is y ≥ 2.

6 0

3 years ago

Please help me I have been stuck on this question for ages

Finger [1]

Answer:28 green and 35 red

Step-by-step explanation:

Given

If there are r red counter and g green counter then

Probability of drawing a green counter is $P(g)=\frac{4}{9}$

and $P(g)=\frac{\text{No of g counter}}{\text{Total no of counter}}$

Thus $\frac{\text{No of g counter}}{\text{Total no of counter}}=\frac{4}{9}$

$\frac{g}{g+r}=\frac{4}{9}$

$\Rightarrow 9g=4g+4r$

$\Rightarrow 5g=4r\quad \ldots(i)$

Also if 4 red and 2 green counter is added the probability of drawing a green counter is

$P(g)=\frac{10}{23}=\frac{\text{No of g counter}}{\text{Total no of counter}}$

$\Rightarrow \frac{10}{23}=\frac{g+2}{g+2+r+4}$

$\Rightarrow \frac{10}{23}=\frac{g+2}{g+r+6}$

$\Rightarrow 10g+10r+60=23g+46$

$\Rightarrow 10r+14=13g\ quad \ldots(ii)$

Substitute the value of g in equation (ii)[/tex]

$\Rightarrow 10\times \frac{5}{4}g+14=13g$

$\Rightarrow \frac{25}{2}g+14=13g$

$\Rightarrow g=28$

Therefore $r=35$

Thus there 28 green counter and 35 red counter

6 0

3 years ago