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AysviL [449]
3 years ago
11

Name the property the equation illustrates.

Mathematics
2 answers:
qwelly [4]3 years ago
6 0

Answer:

Option D is correct

Commutative Property of Addition

Step-by-step explanation:

Commutative property of addition states:

for any number x and x we have;

x+y = y+x

As per the statement:

Consider:

8+3.4

By commutative property of addition we get;

3.4+8

⇒8 + 3.4 = 3.4 + 8

Therefore, the property the equation illustrates is, Commutative Property of Addition

grandymaker [24]3 years ago
5 0
Commutative property
a+b=b+a


D
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ikadub [295]
Pemdas
28/7 + (-19+10)(-4)
28/7+ (-9)(-4)
28/7 + (36)
4+ (36)
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5 0
3 years ago
What is the value of x? 6x−2(x 4)=12 x=?
kykrilka [37]
Let's solve your equation step-by-step.<span><span><span>6x</span>−<span>2<span>x4</span></span></span>=<span>12x</span></span><span><span><span>−<span>2<span>x4</span></span></span>+<span>6x</span></span>=<span>12x</span></span>
Step 1: Subtract 12x from both sides.<span><span><span><span>−<span>2<span>x4</span></span></span>+<span>6x</span></span>−<span>12x</span></span>=<span><span>12x</span>−<span>12x</span></span></span><span><span><span>−<span>2<span>x4</span></span></span>−<span>6x</span></span>=0</span>
Step 2: Factor left side of equation.<span><span><span>2x</span><span>(<span><span>−<span>x3</span></span>−3</span>)</span></span>=0</span>
Step 3: Set factors equal to 0.<span><span><span>2x</span>=<span><span><span>0<span> or </span></span>−<span>x3</span></span>−3</span></span>=0</span><span><span>x=<span><span>0<span> or </span></span>x</span></span>=<span>−1.44225</span></span>
Answer:<span><span>x=<span><span>0<span> or </span></span>x</span></span>=<span>−1.44225 This is the answer if its exponent. The other might be:</span></span>
Step 1: Simplify both sides of the equation.<span><span><span>6x</span>−<span>2<span>(<span>4x</span>)</span></span></span>=<span>12x</span></span><span>
Simplify: (Show steps)</span><span><span>−<span>2x</span></span>=<span>12x</span></span>
Step 2: Subtract 12x from both sides.<span><span><span>−<span>2x</span></span>−<span>12x</span></span>=<span><span>12x</span>−<span>12x</span></span></span><span><span>−<span>14x</span></span>=0</span>
Step 3: Divide both sides by -14.<span><span><span>−<span>14x</span></span><span>−14</span></span>=<span>0<span>−14</span></span></span><span>x=<span>0
You never specified what the (x4) part was so I gave both.</span></span>
8 0
3 years ago
I will mark BRAINILY to first correct answer!! EXTRA POINTSSS!
n200080 [17]
D. 147 i hope it’s right if not i’m so sorry!
7 0
3 years ago
Find the intercept of g(n)=-2(3n-1)(2n+1)
vaieri [72.5K]
To find the intercepts of this give function of g(n), we have to find both the points present on the axis. That is, X-Intercept axial or axis point and the Y-Intercept axial or axis point and apply the zero factor principle to get the actual points on the graph for both the respective intercepts. Let me make it simpler, by showing the whole process via the LaTeX interpreter equation editor.

The X-Intercept is that actual point present in the graphical interpretation where the Y-axis is taken as zero, this makes us to point out the position of X-Intercept points on its X-axis and Y-axis. Take the variable "n" as the variable of "x", it will not change any context or such, we can take any variables for calculations, it does not hinder the processing of Intercepts for the axial points on a graph.

\boxed{\mathbf{\therefore \quad -2(3x - 1)(2x + 1) = 0}}

By the zero factor principle, both of them can be separately calculated as a zero on their either sides of the expression.

\mathbf{\therefore \quad 3x - 1 = 0}

\mathbf{3x - 1 + 1 = 0 + 1}

\mathbf{3x = 1}

\mathbf{\dfrac{3x}{3} = \dfrac{1}{3}}

\mathbf{\therefore \quad x = \dfrac{1}{3}}

Similarly, for the second X-Intercept point for the value of 0 in the Y-axis or Y axial plane in a 2 dimensional Graphical representation is going to be, As per the zero factor principle:

\mathbf{\therefore \quad 2x + 1 = 0}

\mathbf{2x + 1 - 1 = 0 - 1}

\mathbf{2x = - 1}

\mathbf{\dfrac{2x}{2} = \dfrac{- 1}{2}}

\mathbf{\therefore \quad x = -\dfrac{1}{2}}

Then the X-Intercept here becomes with our provided points as:

\boxed{\mathbf{\underline{X-Intercept: \quad \Bigg(\dfrac{1}{3}, \: 0 \Bigg), \: \: \: \: \Bigg(-\dfrac{1}{2}, \: 0 \Bigg)}}}

Therefore, for our Y-Intercept axial point the X axial plane will instead turn out to be a value with zero on a Graphical representation to obtain the actual points for Y-axis and the Y-Intercept for x = 0 as a point on the graph itself.

Just substitute the value of "0" in "x" axis as a variable on the provided expression. Therefore:

\boxed{\mathbf{= -2(3 \times 0 - 1) (2 \times 0 + 1)}}

\mathbf{y = - 2 (0 - 1) (0 + 1)}

\mathbf{y = - 2 (- 1) (0 + 1)}

\mathbf{y = - 2 (- 1) \times 1}

\mathbf{y = 2 \times 1 \times 1}

\mathbf{\therefore \quad y = 2}

Then, the Y-Intercept would definitely be as per the X-axis lying on the point of zero.

\boxed{\mathbf{\underline{Y-Intercept: \quad \big(0, \: 2 \big)}}}

The final coordinating points for X-Intercept and Y-Intercept for their X-axis and Y-axis will be.

\boxed{\mathbf{\underline{X \: Intercepts: \: \: \Bigg(\dfrac{1}{3}, \: 0 \Bigg), \: \: \: \: \Bigg(-\dfrac{1}{2}, \: 0 \Bigg); \: \: Y \: Intercepts: \: \: \big(0, \: 2 \big)}}}

Hope it helps.
6 0
4 years ago
The length and width of a rectangle are in a 3:5 ratio. The perimeter of the rectangle is 64. What are the length and width of t
BlackZzzverrR [31]
3:5 = 64cm
3x+5x= 64
8x=64
x=8

Therefore,

3x=8×3
=24

5x=8×5
=40

3x+5x=64cm
3 0
3 years ago
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