0.433 is rounded to the hundredths already, so to round it to the nearest tenths, just remove the last number.
Your answer is going to be 0.43
Answer:
(1238.845 ;1285.376)
Step-by-step explanation:
Conditions for constructing a confidence interval :
Data must be random
Distribution should be normal and independent ;
Based on the conditions above ; data meets initial conditions ;
C. I = sample mean ± margin of error
Given the data :
1241 1210 1267 1314 1211 1299 1246 1280 1291
Mean, xbar = Σx / n = 11359 / 9 = 1262.11
The standard deviation, s = [√Σ(x - xbar)²/n - 1]
Using a calculator ; s = 37.525
The confidence interval :
C.I = xbar ± [Tcritical * s/√n]
Tcritical(0.10 ; df = n - 1 = 9 - 1 = 8)
Tcritical at 90% = 1.860
C. I = 1262.11 ± [1.860 * 37.525/√9]
C.I = 1262.11 ± 23.266
(1238.845 ;1285.376)
± 23.266
The margin of error :
[Tcritical * s/√n]
[1.860 * 37.525/√9]
C.I = ± 23.266
None of the alternatives are correct. The domain's lower bound is 6, however it contains 6, therefore a bracket is required rather than a parenthesis. [6 (infinity)] Because infinity is not included, a bracket for infinity is invalid. The range is from 0 to infinity. assuming you meant 1/sqr (x-6). However, none of the options are right if you meant 1/(sqr(x) - 6).
or did you mean 1/sqrx - 6? However, none of them are correct.
No they do not. For example, on a number line with the numbers -2 and 2, they are in different locations on a number line. -2 is farther on the left, while 2 is farther on the right. Therefore, opposites do not name the same location on a number line!
Answer:
Just substitute x with 3.the answer should be - 26.
Step-by-step explanation:
