Simplify the expression. 5 + 4 • (8

What is 210 divided by 2 1/2

ki77a [65]

Answer:

210 divided 2 1/2= 84....

6 0

4 years ago

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Class 10R sat a test.

Gnesinka [82]

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5 0

3 years ago

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The water in a pool evaporates at a rate of 16 gallons per week. What integer represents the change in the number of gallons of

Sav [38]

If 16 gallons of water evaporates per week and we have 24 weeks, we can jsut multiply it.
So $16*24=384$ gallons of water evaporates.

6 0

3 years ago

A rock is thrown down with a velocity of 20 feet per second from a hot air balloon that is 220 feet above the ground. How long w

kupik [55]

Answer:

It takes the rock approximately 4.96 seconds to reach the ground

Step-by-step explanation:

The given parameters of the rock thrown down from the hot air balloon are;

The (initial) downward velocity with which the rock was thrown down, u = 20 feet/second

The height of the balloon when the rock was thrown down, h = 220 feet

According to the kinetic equation of motion, we have;

h = u·t + (1/2)·g·t²

Where;

h = The height of the rock when it was thrown = 220 ft.

u = The initial velocity of the rock = 20 ft./s

g = The acceleration due to gravity acting on the rock = 9.81 m/s²

t = How long it takes the rock to reach the ground

Plugging in the values gives;

220 = 20·t + (1/2)×9.81×t²

4.905·t² + 20·t - 220 = 0

Therefore;

t = (-20 ± √(20² - 4×4.905×(-220)))/(2 × 4.905)

t ≈ 4.96, or t ≈ -9.04

Therefore, the time it takes the rock to reach the ground, t ≈ 4.96 seconds.

5 0

3 years ago

Create a question with this scenario you could ask that could be answered only by graphing or using logarithm.

Vesnalui [34]

Answer:

After how many years is the fish population 100?

x=3.97 years

Step-by-step explanation:

The fish population increases by a factor of 1.5 each year. We have the equation that represents this situation

$f (x) = 20 (1.5) ^ x$

Where x represents the number of years elapsed f(x) represents the amount of fish.

Given this situation, the following question could be posed

After how many years is the fish population 100?

So we do $f (x) = 100$ and solve for the variable x

$100 = 20 (1.5) ^ x\\\\\frac{100}{20} = (1.5)^x\\\\ 5= (1.5)^x\\\\log_{1.5}(5) = log_{1.5}(1.5)^x\\\\log_{1.5}(5) = x\\\\x =log_{1.5}(5)\\\\x=3.97\ years$

Observe the solution in the attached graph

8 0

3 years ago

Simplify the expression. 5 + 4 • (8 – 6)2