1. Selection B is the only equation satisfied by both (0, 5) and (2, -1).
2. Selection D is the only one with a slope of 5/2.
In the problem of insufficient data quantities. I can get a general solution.We know that tangent to a circle is perpendicular to the radius at the point of tangency. It's mean that triangles LJM and LJK are rights.
Let angle JLK like X.
So, angle JLM=61-x.
And it's mean that by using right triangle trigonometry
Radius MJ = LM*cos(61-X)
4x=9y+2
x=(9y+2)/4
11x-8=90+9y+2
11((9y+2)/4)-8=9y+92
(99y+22)/4=9y+100
99y+22=36y+400
63y=378
y=6
x=14
is the question asking for y or x？？or is it asking for angle
First we will find the value of x.
To find the value of x we can add angle Q and angle O and set them equal to 180 and solve for x.
We will be setting them equal to 180 since the opposite angles of an inscribed quadrilateral are supplementary.
angle Q + angle O = 180
6x - 5 + x + 17 = 180
7x +12 = 180
7x = 168
x = 24
Now we can use 24 for x and find the value of angle QRO
angle QRO = 2x + 19
angle QRO = 2(24) + 19
angle QRO = 48 + 19
angle QRO = 67
So the answer choice B is the right answer.
Hope this helps :)<span />
