Question

Emily has 12 fruits in her bowl. She has 3 apples, 5 bananas, 1 pear and 3 oranges. A fruit is selected at random. What is the probability that the fruit is an orange or a pear?
5/6

1/3

1/2

2/3

Answer 1

Since there are 3+1=4 fruits that are oranges or pears, there is a 4/12 or 1/3 chance to get an orange or a pear.

Answer 2

Answer:

Option B is correct.

The probability that the fruit is an orange or a pear = $\frac{1}{3}$

Step-by-step explanation:

Given the statement: Emily has 12 fruits in her bowl. She has 3 apples, 5 bananas, 1 pear and 3 oranges.

Probability states that it is the chance or likelihood that an event will happen.

Also, It is the ratio of the number of ways an event can occur to the number of possible outcomes.

Total number of possible outcomes = 12

A : Event that the fruit is an orange

B : Event that the fruit is an Pear

P(A) = $\frac{3}{12} = \frac{1}{4}$

P(B) = $\frac{1}{12}$

Probability that the fruit is an orange or a pear =$P(A) + P(B)$ = $\frac{1}{4} +\frac{1}{12}=\frac{3+1}{12} = \frac{4}{12} = \frac{1}{3}$