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3 years ago

PLEASE HELP ME !!!!

Mathematics

1 answer:

VikaD [51]3 years ago

7 0

9514 1404 393

Answer:

C. More than 1 solution

Step-by-step explanation:

Divide the second equation by 3.

y -x = -3

Add x.

y = x -3

This matches the first equation exactly, meaning that any solution to the first equation is also a solution to the second equation. There are an infinite number of possibilities. There is "More than 1 solution."

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70 liters ÷ 100 samples= 0.7 or 7/10 liter per sample

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3 years ago

Read 2 more answers

Bob and mark talk about their families.bob says he has three kids, the product of Their age is 72. He gives another clue: the su

drek231 [11]

Bob says he has 3 kids, the product of their age is 72.
So the possible ages of Bob's kids can be taken from the factors of 72

72 = 2 * 2 * 2 * 3 * 3

Finally, bob says, my youngest child called justice.
So meaning, Bob has a youngest child. He didn't mention about a twin.

So the possible ages the following:
1, 2, 36 --> sum: 39
1, 4, 18 --> sum: 23
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Once the sum of the ages will be revealed, then the possible ages are mentioned above.

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3 years ago

sonja wants to have $14000 in 13 years. calculate how much she should invest now at 6% interest, compounded semiannually in orde

mariarad [96]

She should invest $6491.73.

The equation we use to solve this is in the form
$A=p(1+\frac{r}{n})^{nt}$ ,
where A is the total amount in the account, p is the principal invested, r is the interest rate as a decimal, n is the number of times per year the interest is compounded, and t is the amount of time.

A in our problem is 14000.
p is unknown.
r is 6% = 6/100 = 0.06.
n is 2, since it is compounded semiannually.
t is 13.

$14000=p(1+\frac{0.06}{2})^{13*2}
\\
\\14000=p(1+0.03)^{26}
\\
\\14000=p(1.03)^{26}
\\
\\\text{Dividing both sides by }1.03^{26}\text{, we have}
\\
\\\frac{14000}{1.03^{26}}=\frac{p(1.03)^{26}}{1.03^{26}}
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3 years ago

Based on information from Consumer Reports, a random sample of 35 thirty-gram cookies had a sample mean of 146 calories. The sta

Nonamiya [84]

Using the z-distribution, it is found that the 90% confidence interval for mean calories in a 30-gram serving of all chocolate chip cookies is (143, 149).

We are given the standard deviation for the population, which is why the z-distribution is used to solve this question.

The information given is:

Sample mean of $\overline{x} = 146$ .

Population standard deviation of $\sigma = 12$ .

Sample size of $n = 65$ .

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

The critical value, using a z-distribution calculator, for a 95% confidence interval is z = 1.645, hence:

$\overline{x} - z\frac{\sigma}{\sqrt{n}} = 146 - 1.645\frac{12}{\sqrt{35}} = 143$

$\overline{x} + z\frac{\sigma}{\sqrt{n}} = 146 + 1.645\frac{12}{\sqrt{35}} = 149$

The 90% confidence interval for mean calories in a 30-gram serving of all chocolate chip cookies is (143, 149).

A similar problem is given at brainly.com/question/16807970

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2 years ago

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