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Elan Coil [88]
4 years ago
12

Find X for each one of the following

Mathematics
1 answer:
Sveta_85 [38]4 years ago
5 0
X = 11.7

Hope this helped! :)
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159.98 divided by 6 <br><br> ASAPP
ArbitrLikvidat [17]

159.98 divided by 6 is 26.66, hopefully this is correct...

4 0
4 years ago
Which of the following comparisons is False
Verizon [17]
A graph shows the first comparison is true, and the C temperature is cooler than the F temperature for the remaining comparisons.

The comparison that is FALSE is ...
  C.....30 °C is warmer than 90 °F

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30 °C = 86 °F
32.2 °C ≈ 90 °F

4 0
4 years ago
The price of an item has been reduced by 85% . The original price was $45. What is the price of the item now.
Kobotan [32]

Answer:the price for the item now it's 6.75


Step-by-step explanation:

Origin price is 45=100% after reduction comes to 85% =x

X stands for the unknown value of the reduction therefore

45=100%

X=85%

45*.85=100x


After calculation you realised the value of x reduction value it's 38.25


Hence, original price is 45 your less from the value reduced 38.25 therefore the value of the item is 6.75

3 0
3 years ago
The half life of a certain substance is about 4 hours. The graph shows the decay of a 50 gram sample of the substance that is me
olga55 [171]
I can't see how any of those formulas show exponential decay.  (Did you type those correctly?)

The formula that will show the remaining amount correctly is:
ending amount = Bgng Amount / 2^n
where "n" is the number of haf-lives.

So, for example if half life = 4 hours and if we want to calculate the amount after 9 hours (that's 2.25 half-lives) then:
ending amount = Bgng Amount / 2^n
ending amount = 50 / (2^(9/4))
ending amount = 50 / 2^2.25
ending amount = 50 / <span><span><span>4.75682846 </span>
</span></span><span><span>ending amount = </span> 10.5112 grams
</span>Looking at the graph, we see that's about right.
 

7 0
3 years ago
Read 2 more answers
Simplify <br><br>(x^a)^b-c×(x^b)^c-a×(x^c)^a-b<br><br>step by step...
Korvikt [17]

Answer:

= (xa+b)a-b .(xb+c)b-c. (xc+a)c-a

Or

= x(a+b)(a-b). x(b+c)(b-c) .x(c+a)(c-a)

7 0
3 years ago
Read 2 more answers
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