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Yuri [45]
2 years ago
5

12 + 6 − 4 ÷ (2 + 5)

Mathematics
1 answer:
DiKsa [7]2 years ago
5 0
PEMDAS: Parantheses first

Answer: B) Add 2 and 5.
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the art club receives $10 plus $2 for every sculpture they sell for a fundraiser. the expression 2x+10 represents the amount the
Len [333]
2x + 10...the common number between these 2 terms is 2...so factor the 2 out

2(x + 5) <==
8 0
3 years ago
Estimate the square root to the nearest integer.
nexus9112 [7]
Answer:
3
Explanation:
3^2 is equal to 9, and 4^2 is equal to 16, so sqrt(10) must be in between 9 and 16. Since 10 is closer to 9 than to 16, sqrt(10) is closer to 3 than 4, which means that to the nearest integer sqrt(10)=3
3 0
2 years ago
Answer and explanation please!!
Mandarinka [93]

Answer:

Area of the rhombus, A = 22.5 sq. ft.

Step-by-step explanation:

The area of a rhombus = a. b

where, a = side of the rhombus

and      b = height of the rhombus.

Here, the side, a = 5 ft

Height, b = 4.5 ft.

Therefore, area, A = 5 X 4.5 sq. ft

⇒ A = 22.5 sq. ft which is the required answer.

5 0
2 years ago
terry opened a savings account in December with $132 and saved $27 each month beginning in January the value of terrys account i
liq [111]
Let S be the amount in a savings account. 
Let m be the number of months.

General equation
S = 132 + 27m

Specific question
July is the 7th month of the year including both January and July.
S = 132 + 7*27
S = 132 + 189
S = 321

Reasonableness?
Good question. You could estimate an answer.
Start with 150 dollars and say that you add 25 a month.
7 * 25 = 175
S = 150 + 175 = 325 All of this was done in my head. Since the exact answer obtained using the formula is 321, I think that's pretty reasonable using my estimate is a guide.
4 0
3 years ago
HELP I'M SOOOOOO ANGRYYYYY PLEASE HELPPPP<br>determine the values of X for which g(x) is defined​
tiny-mole [99]

Answer: Any real number x as long as x \ne 0 and x \ne -\frac{2}{3}

In other words, anything but 0 or -2/3 is valid.

========================================================

Explanation:

Set the denominator equal to zero and solve for x

2(3x^2 + 2x) = 0

3x^2 + 2x = 0

x(3x + 2) = 0

x = 0 or 3x+2 = 0 .... zero product property

x = 0 or 3x = -2

x = 0 or x = -2/3

If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x)  will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.

Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.

7 0
3 years ago
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