There are 10,000 total four-digit numbers (1000 through 9999).
Multiples of 2 end in 0, 2, 4, 6, and 8. There are 9*10*10*5 = 4500 four-digit multiples of 2.
Multiples of 5 end in 0 or 5. There are 9*10*10*2 = 1800 four-digit multiples of 5.
There is redundancy between the two sets of numbers, namely those that end in 0, which are both multiples of 2 and 5. There are 9*10*10*1 = 900 four-digit multiples of both 2 and 5.
Then there are 4500 + 1800 - 900 = 5400 total four-digit numbers that are either multiples of 2 or 5, which means the remaining 4600 numbers are neither multiples of 2 nor 5.
Hey there :)
Writing in scientific notation means a should be
0 ≤ a < 10
Therefore, 0.000309 will be written as
3.09 x 10ⁿ
3 is the 4th decimal place value
so n = - 4
3.04 x 10⁻⁴
Just substitute x = 2 and y = 5 into the equation wherever you see x and y.
2 + (12 - 5x) · 2y
2 + (12 - 5(2)) · 2(5)
2 + (2) · 10
4 · 10
40, is the answer which should be the first box.
S= Sydney
devaughn= s-13
so s+s-13=75
2s-13=75
now I think you can solve the rest.
Step-by-step explanation:
4- 0.25 + 0.5h
0.25g= 2.5
4- 2.5 = 1.5
0.5h = 2.5
4- 2.5 + 2.5
addition is first
2.5+2.5 = 5
4-5 =-1
I honestly don't know if that's right but I tried aha x
