Answer:
=x⁴−x³−14x²
Step-by-step explanation:
<h3>Let's simplify step-by-step.</h3>
x²(3x²+5x−4)−2x²(x²+3x+5)
<h3>Distribute:</h3>
=(x²)(3x²)+(x²)(5x)+(x²)(−4)+−2x⁴+−6x³+−10x²
=3x⁴+5x³+−4x²+−2x⁴+−6x³+−10x²
<h3>Combine Like Terms:</h3>
=3x⁴+5x³+−4x²+−2x⁴+−6x³+−10x²
=(3x⁴+−2x⁴)+(5x³+−6x³)+(−4x²+−10x²)
=x⁴+−x³+−14x²
<h3>ANS-</h3>
=x⁴−x³−14x²
Answer:
423 miles and that was found by subtracting 750 from 1000 and dividing that by 0.59
Answer: y=mx+b
Step-by-step explanation:
Answer:
Population mean = 7 ± 2.306 × 
Step-by-step explanation:
Given - A university researcher wants to estimate the mean number
of novels that seniors read during their time in college. An exit
survey was conducted with a random sample of 9 seniors. The
sample mean was 7 novels with standard deviation 2.29 novels.
To find - Assuming that all conditions for conducting inference have
been met, which of the following is a 94.645% confidence
interval for the population mean number of novels read by
all seniors?
Proof -
Given that,
Mean ,x⁻ = 7
Standard deviation, s = 2.29
Size, n = 9
Now,
Degrees of freedom = df
= n - 1
= 9 - 1
= 8
⇒Degrees of freedom = 8
Now,
At 94.645% confidence level
α = 1 - 94.645%
=1 - 0.94645
=0.05355 ≈ 0.05
⇒α = 0.5
Now,

= 0.025
Then,
= 2.306
∴ we get
Population mean = x⁻ ±
×
= 7 ± 2.306 × 
⇒Population mean = 7 ± 2.306 × 