Use the hypergeometric distribution.
M=number of Men=5
F=number of women=4
m=number of men elected=2
f=number ow women elected=2.
Assuming equal chance to get elected, then
P(2M,2F)=C(M,m)*C(F,f)/C(M+F,m+f)
=C(5,2)*C(4,2)/C(9,4)
=10*6/126
=10/21
Reference: Hypergeometric distribution.
Answer:
everyone except his smaller siblings will be older than him
Step-by-step explanation:
if you need the correct answer say the full question you
dumb
Answer:
Colin has <em>8 sheets </em>left for his third class.
Step-by-step explanation:
Given that:
Total Number of pieces of papers = 
Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad
Writing the equation:

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

So, the answer is:
Colin has <em>8</em> <em>sheets </em>left for his third class.
5,270 is 5,267.82 rounded to the nearest ten
hope this helps
Answer to what? I’m confused lol