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Sladkaya [172]
3 years ago
14

Jeff wanted to see how many smaller boxes will fit into the larger box. Each small box has a side length of 1.5 inches. The larg

er box has a side length of 5 inches. How many small boxes fit into big boxes
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
6 0

Answer:

 3

Step-by-step explanation:

1.5+1.5+1.5= 4.5

4.5 is smaller than 5

Hope this helps

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There are 9 candidates total, 5 male and 4 female, who run for 4 committee positions. Suppose that each person is equally likely
gavmur [86]
Use the hypergeometric distribution.
M=number of Men=5
F=number of women=4
m=number of men elected=2
f=number ow women elected=2.

Assuming equal chance to get elected, then
P(2M,2F)=C(M,m)*C(F,f)/C(M+F,m+f)
=C(5,2)*C(4,2)/C(9,4)
=10*6/126
=10/21

Reference: Hypergeometric distribution.

6 0
3 years ago
If Gary is 11 years old how old are each of the family members
Korolek [52]

Answer:

everyone except his smaller siblings will be older than him

Step-by-step explanation:

if you need the correct answer say the full question you

                     dumb

3 0
3 years ago
Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the p
PIT_PIT [208]

Answer:

Colin has <em>8 sheets </em>left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = x

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8

So, the answer is:

Colin has <em>8</em> <em>sheets </em>left for his third class.

5 0
3 years ago
Round 5,267.82 to the nearest ten
LiRa [457]
5,270 is 5,267.82 rounded to the nearest ten
hope this helps

5 0
3 years ago
Please help me, just need the answer and thank you!
Triss [41]
Answer to what? I’m confused lol
6 0
3 years ago
Read 2 more answers
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