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Black_prince [1.1K]
4 years ago
12

Which ordered pairs are a solution to the equation?

Mathematics
1 answer:
fenix001 [56]4 years ago
3 0
The ordered pairs that are a solution to the equation y=4-2x are (0,4) and (-1,6)
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Raul has 56 bouncy balls. he puts three times as many balls into red gift bags as he puts into green gift bags. if he puts the s
Oksi-84 [34.3K]

Raul has 56 bouncy balls

he puts the balls into red gift bags and green gift bags

so lets say he puts x number of balls into green gift bags

then we are told that he puts three times as many balls into red gift bags as he puts into green gift bags

so the number of balls he puts into red gift bags is - 3 * x = 3x

the total number of balls = 56

so we can write the following equation

x + 3x = 56

4x = 56

x = 56/4

x = 14

therefore the amount of balls he puts into green bags is - 14 balls


6 0
3 years ago
Read 2 more answers
T- 4t^2 + 2t^3<br> What is the degree of the polynomial?
Eduardwww [97]

Answer:

3rd degree

Step-by-step explanation:

The highest exponent is a 3, meaning this is a 3rd degree polynomial.

4 0
3 years ago
Anna makes 120 dolls each month to sell. This month, she increases the number of dolls she makes by 30%. How many dolls does Ann
scoray [572]
120 * .30 (30%) = 36
120+36 = 156
4 0
3 years ago
The area of a triangle is comtinous or discrete
Colt1911 [192]

Answer:

Continuous

Step-by-step explanation:

The area of a triangle is continuous. It can be any measure of fraction or decimal depending on the side lengths. It has no restrictions to be only whole  numbers or a specific set of numbers.

3 0
3 years ago
You roll 4 fair, distinguishable, six-sided dice. What is the probability of rolling :______
Vikentia [17]

Answer:

a)0.25

b)0.375

Step-by-step explanation:

Possible outcomes when dice are rolled : 1 ,2 ,3,4,5 ,6

Even= 2,4,6  

Odd = 1 ,3 , 5

Probability of getting even =\frac{3}{6}=\frac{1}{2}

Probability of getting odd = \frac{3}{6}=\frac{1}{2}

4 dices are rolled together

a)P(3 even and 1 odd numbers)

P(3 even and 1 odd numbers)=^4C_3 (\frac{1}{2})^3 (\frac{1}{2})^1

P(3 even and 1 odd numbers)=\frac{4!}{3!1!} (\frac{1}{2})^3 (\frac{1}{2})^1 =0.25

b)P(2 even and 2 odd numbers)

P(2 even and 2 odd numbers)=^4C_2 (\frac{1}{2})^2 (\frac{1}{2})^2

P(3 even and 1 odd numbers)=\frac{4!}{2!2!} (\frac{1}{2})^2 (\frac{1}{2})^2=0.375

6 0
3 years ago
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