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il63 [147K]
3 years ago
13

Draw any ∆ ABC with ^B = 90°​

Mathematics
2 answers:
kupik [55]3 years ago
3 0
Draw a right angle triangle and label b as the corner
oee [108]3 years ago
3 0

Answer:

In ∆ABC, ∆CBA, ∆ACB

^B = 90°

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1.7.3 Quiz: interacting lines and proofs Question 2 of 10
Kryger [21]

Answer:

C. ∠SOE and ∠DOA

D. ∠EOA and ∠DOS

Step-by-step explanation:

Vertical angles are congruent angles.

From the given figure, the vertical angles are...

∠SOE and ∠DOA

∠EOA and ∠DOS

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5 0
2 years ago
Solve for a: 1/4a-17=-15
MAXImum [283]
1/4a-17=-15
1/4a=-15+17
1/4a=2
(1/4*4)a=(2*4)
a=8

4 0
4 years ago
Round to the nearest Tenth.
choli [55]
26.04 I think I am not really sure what the question is asking
3 0
3 years ago
I need an answer for this lolz
Ksenya-84 [330]

Answer:

Where is the coordinate plane?

Step-by-step explanation:

4 0
3 years ago
Match each value with its formula for ABC.
Ivahew [28]

For the triangle ABC use the sine theorem:

\dfrac{a}{\sin A}= \dfrac{b}{\sin B}= \dfrac{c}{\sin C}.

1. From \dfrac{a}{\sin A}= \dfrac{b}{\sin B} you have \dfrac{a}{b} \cdot \sin B=\sin A.

2. From \dfrac{b}{\sin B}= \dfrac{c}{\sin C} you have \dfrac{b}{c} \cdot \sin C=\sin B.

3. From \dfrac{a}{\sin A}= \dfrac{c}{\sin C} you have \dfrac{c}{a} \cdot \sin A=\sin C.

4. From \dfrac{a}{\sin A}= \dfrac{c}{\sin C} you have \dfrac{\sin A}{\sin C} \cdot c=a.

5. From \dfrac{a}{\sin A}= \dfrac{b}{\sin B} you have \dfrac{\sin B}{\sin A} \cdot a=b.

6. From \dfrac{b}{\sin B}= \dfrac{c}{\sin C} you have \dfrac{\sin C}{\sin B} \cdot b=c.

5 0
4 years ago
Read 2 more answers
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