Draw any ∆ ABC with ^B = 90°

Mathematics

2 answers:

kupik [55]3 years ago

3 0

Draw a right angle triangle and label b as the corner

oee [108]3 years ago

3 0

Answer:

In ∆ABC, ∆CBA, ∆ACB

^B = 90°

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Help ME! solve for ∠K.

Ainat [17]

Answer:

Step-by-step explanation:

Every Triangle has 180 degrees.

x + 8x + 3x = 180

12x = 180

x = 180/12

x = 15

Angle K = 3x

K = 3 * 15

K = 45

3 0

3 years ago

Please solve all four questions!!1 brainliest and 25 pts

rodikova [14]

I can answer only 1st coz I have no idea about 2nd problem..

Here Hypotenuse is 5

$c{}^{2} = a {}^{2} + b {}^{2}$

a =x

b =4

c = 5

5 square =x square +4 square..

25 =x square+16

25 -16 =x square

9 =x square..

√9 = x

3 = x..

<h2>If this answer helps you plz mark as brainlist..</h2>

8 0

3 years ago

Read 2 more answers

A cheerleading squad consists of ten cheerleaders of ten different heights. How many ways are there for the cheerleaders to line

Sindrei [870]

Answer:

11340

Step-by-step explanation:

We have 10 cheerleaders of ten different heights. There are two rows each having 5 positions so that five cheerleaders occupy the first row that have height less than the five cheerleaders who occupied the second row.

Therefore, Out of ten cheerleaders, two cheerleaders will be selected out of which the tallest one will occupy the position in the upper row and the second one will occupy in the lower row, therefore these two positions will be occupied in $10C_{2}$ ways. Now, we are left with 8 cheerleaders and following the same path, the next two positions will also be occupied in $8C_{2}$ ways, similarly, following the same path, the number of ways the cheerleaders will occupy the position will be: $10C_{2}$ × $8C_{2}$ × $6C_{2}$ × $4C_{2}$ × $2C_{2}$