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Sloan [31]
4 years ago
15

Plz help me with this

Mathematics
1 answer:
AnnZ [28]4 years ago
7 0

Answer:  \bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}

<u>Step-by-step explanation:</u>

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, B=\dfrac{6}{5}  →   P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}

Half of that period is: \dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}

Calculate the period for each of the options to find a match:

A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}

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A triangle has vertices at L(2, 2), M(4,4), and N(1,6).
mr Goodwill [35]

Answer:

The rule for the transformation is (x, y) (-x, -y).

The coordinates of L'are (-2,-2).

The coordinates of N'are (-1,-6).

Step-by-step explanation:

Given

L = (2,2)

M = (4,4)

N = (1,6)

Ro=180

Required

Select three options

The rule to this is:

(x,y) \to (-x,-y)

So, we have:

L = (2,2)

L' =(-2,-2)

M = (4,4)

M =(-4,-4)

N = (1,6)

N' = (-1,-6)

7 0
3 years ago
X2-12x+21=-6 solve the quadratic by factoring
yuradex [85]

Answer:

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Step-by-step explanation:

first thing you need to do is move the -6 over. so we're going to add 6 to both sides (we add because it's negative 6 and we need 0 on the right side)

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now we need to come up with two numbers that add to -12 and multiply to 27.

the factors of 27 are 9 & 3 and 27 & 1. only 9 & 3 add to 12 so we are going to use those.

since the 12 is negative however, 9 and 3 should both be negative.

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3 years ago
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erik [133]
A B E

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C = 6 and D = 9 so those are not correct.
7 0
3 years ago
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The equation below has one solution.
monitta

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D

Step-by-step explanation:

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6 0
3 years ago
Which of the following represents the area of a rectangle whose length is 3x + 5 and whose width is x − 2? 3x2 − x − 10 3x2 − 10
never [62]
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A = (3x + 5)(x - 2)
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A = 3x^2 - x - 10 <====

5 0
3 years ago
Read 2 more answers
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