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alisha [4.7K]
3 years ago
15

Rewrite standard form equation in graphing form and then sketch the graph

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
8 0
Türkiye cumhuriyeti ccc
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Line m is parallel to line p. m ∠ HEF = 39º and m ∠ IGF = 13º. Find the m ∠ EFG. Explain in detail how you know you are correct.
svetlana [45]

Answer:

The measure of ∠EFG is 52°

Step-by-step explanation:

Given line m is parallel to line p. m∠HEF = 39º and m∠IGF = 13º.we have to find m∠EFG.

In ΔJFG,

By angle sum property of triangle, which states that sum of all angles of triangle is 180°

m∠FJG+m∠JGF+m∠JFG=180°

⇒ 39°+13°+m∠JFG=180°

⇒ m∠JFG=180°-39°-13°=128°

As JFE is a straight line ∴ ∠JFG and ∠EFG forms linear pair

⇒ m∠JFG+m∠EFG=180°

⇒ 128°+m∠EFG=180°

⇒ m∠EFG=52°

The measure of ∠EFG is 52°

6 0
3 years ago
Simplify 7n - 2n 3p 2p.
andrew11 [14]
7n^{-2}n^3p^2p=7n^{-2+3}p^{2+1}=\boxed{7np^3}
4 0
3 years ago
Use the graph to determine the vertex point of the quadratic function. Is the vertex a
Feliz [49]

Answer:

B) Vertex (1,2), maximum

Step-by-step explanation:

First, determine if the graph has a maximum or a minimum value. Since the graph opens downwards, it has a <u>maximum</u> value.

The maximum is the point that has the greatest y value. We can see that the greatest y value is at y=2. Going down two units from that spot, we can see that the x value is at x=1. We can plug those into the vertex form, (x,y). By plugging in we get the point (1,2).

5 0
2 years ago
Complete the steps to find the value of x
vampirchik [111]
72, 96, 84, 12

72 + (7x+24) = 180
7x + 96 = 180
7x = 84
x = 12
3 0
3 years ago
Fibonacci posed the following problem: Suppose that rabbits live forever and that every month each pair produces a new pair whic
docker41 [41]

Answer:

Let f_n be the number of rabbit pairs at the beginning of each month. We start with one pair, that is f_1 = 1. After one month the rabbits still do not produce a new pair, which means f_2 = 1. After two months a new born pair appears, that is f_3 = 2, and so on. Let now n \geq 3 be any natural number. We have that f_n is equal to the previous amount of pairs f_n-1 plus the amount of new born pairs. The last amount is f_n-2, since any two month younger pair produced its first baby pair. Finally we have  

f_1 = f_2 = 1,f_n = f_n-1 + f_n-2 for any natural n  \geq 3.  

5 0
3 years ago
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