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3 years ago

Determine which postulate or theorem can be used to prove that LMN PMN.

Mathematics

2 answers:

tatiyna3 years ago

8 0

SAS (Side angle side) would be right

likoan [24]3 years ago

3 0

SAS as LN is congruent to PN and angleLNM is congruent to angle PNM also, MN is a shared side which is reflexive property.

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A website manager has noticed that during the evening hours, about 3.23.2 people per minute check out from their shopping cart

aleksandrvk [35]

Answer:

1. c. Poisson

2. 0.9592 = 95.92% probability that in any one minute at least one purchase is made.

3. 0.0017 = 0.17% probability that no one makes a purchase in the next 2 minutes.

Step-by-step explanation:

We have only the mean, which means that the Poisson distribution is used to solve this question, and thus the answer to question 1 is given by option c.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Mean of 3.2 minutes:

This means that $\mu = 3.2n$ , in which n is the number of minutes.

2. What is the probability that in any one minute at least one purchase is made?

$n = 1$ , so $\mu = 3.2$ .

This probability is:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-3.2}*3.2^{0}}{(0)!} = 0.0408$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0408 = 0.9592$

0.9592 = 95.92% probability that in any one minute at least one purchase is made.

3. What is the probability that no one makes a purchase in the next 2 minutes?

2 minutes, so $n = 2, \mu = 3.2(2) = 6.4$

This probability is P(X = 0). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-6.4}*6.4^{0}}{(0)!} = 0.0017$

0.0017 = 0.17% probability that no one makes a purchase in the next 2 minutes.

7 0

3 years ago

Evaluate.<br> (-5)5<br> Enter your answer in the box.

Klio2033 [76]

Answer:

The answer is -25

Step-by-step explanation:

7 0

3 years ago

The countries population in 1991 was 231 million . In 1999 it’s was 233 million. estimate the population in 2003 used The expone

liraira [26]

Answer:

The population in 2003 was 234 million

Step-by-step explanation:

In order to calculate the population in 2003 we would have to use the The exponential growth formula as follows:

p(y)=ir^t

According to the given data:

p(y)=233 million

i=231 million

t =1999-1991

Therefore, 233 million=231 million r^(1999-1991)

(233 million/231 million)^(1/8)=r

p(y)=231 million(233 million/231 million)^((y-1991)/8)

Therefore, in 2003 p(2003)=231 million(233 million/231 million)^((2003-1991)/8)

p(2003)=231 million(233 million/231 million)^(1.5)

p(2003)=234 million

The population in 2003 was 234 million

7 0

4 years ago

Can three go into 5 in division

m_a_m_a [10]

Yes but it would result in a decimal.

4 0

4 years ago

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What is the surface area of the figure?

anyanavicka [17]

Answer:

24 is what I got

Just find the are of each shape and add the answers together to get the total area of the figure

7 0

4 years ago

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